The driver of a car traveling at a speed of 27 m/s slams on the brakes and comes to a stop in 3 s. If we assume that the speed c
1 answer:
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F = Magnetic Force
B = Magnetic Field
V = Velocity
*The vectors from the photo you get doing the left-hand rule.
The magnetic force is always perpendicular to the magnetic field.
And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.
The formula to find the Magnetic Force is:
Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.
Newton (N) = C x m/s x T = (C x m x T)/s
B = Magnetic Field
V = Velocity
*The vectors from the photo you get doing the left-hand rule.
The magnetic force is always perpendicular to the magnetic field.
And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.
The formula to find the Magnetic Force is:
Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.
Newton (N) = C x m/s x T = (C x m x T)/s
Answer:
Explanation:
Most of the power developed by the engine is used to compensate for the mechanical energy loss due to frictional forces because these are the only forces on the horizontal direction the automobile is subjected to, besides of that generated by the engine itself. If the automobile is moving at constant speed, then these the force the engine provides is equal to the total friction force acting on the car.
We calculate then the force the engine provides. We know that power relates to work by the equation , and that work relates to force by the equation
, so combining them we have:
Which can be written as:
And since are
, for our values the force the engine provides is:
Which is also then the total friction force acting on the car.