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ale4655 [162]
3 years ago
9

During a solar eclipse the Moon is positioned directly between Earth and the Sun.

Physics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

Ft = - 23.99 10₁₉₉9 N

Explanation:

In this exercise we will use the law of universal gravitation

        F = G m₁ M₂ / r²

With Newton's second law we get

        Ft = F1 - F2

Where F1 is the force of attraction between the moon and the Earth

       F1 = G m₁ M₂ / r²

       F1 = 6.67 10⁻¹¹  7.36 10²² 5.98 10²⁴ /(3.84 10⁸)²

       F1 = 19,909 10¹⁹ N

Let's calculate the force of attraction between the Sun and the moon (F2)

The distance from the sun to the moon is the distance from the sun to the Earth minus the distance from the earth to the moon

        R = 1,496 10¹¹ - 3.84 10⁸ = (1496 - 3.84) 10⁸ m

        R = 1492.2 108 m

        F2 = 6.67 10⁻¹¹ 7.36 10²² 1,991 10³⁰ /(1492.2 10⁸)²

        F2 = 4.3896 10²⁰

        Ft = 19,902 10¹⁹ - 43,896 10¹⁹

        Ft = - 23.99 10₁₉₉9 N

The negative sign indicates that the force is directed towards the sun

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