Answer:
50 m
Explanation:
F = ma
10 N = (10 kg) a
a = 1 m/s²
Given:
v₀ = 0 m/s
a = 1 m/s²
t = 10 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1 m/s²) (10 s)²
Δx = 50 m
Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.
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I looked this up
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Answer:
2m/s/s
Explanation:
The formula goes- F=MA
F-Force M-Mass & A-Acceleration
We need to rearrange this formula to find the acceleration-
A=F/M
All we need to do now is substitute the values in
A=2000N/1000kg
A=2m/s^2
In the given option the last option (2m/s/s) would be the ans, as it's the same as 2m/s^2
So ya, I guess that's all
Hi, thank you for posting your question herein Brainly.
These physical changes could be classified based on their energy requirements: endothermic or exothermic. Endothermic reaction need to absorb energy, while exothermic reaction need to release the energy in order to achieve spontaneous reactions.
Exothermic: Condensation, Freezing, Deposition
Endothermic: Sublimation, Evaporation, Melting