Suppose you wanted to be able to see astronauts on the moon. What is the smallest diameter of the objective lens required to res
1 answer:
You might be interested in
Answer:
(a) 1.2703×10⁻⁷ m
(b) 4.7636×10⁻⁸ m
(c) 2.5406×10⁻⁸ m
Explanation:
Given:
Width of the infinite well, L = 340 pm = 340×10⁻¹² m.
The formula for energy of the electron in nth state is:
The expression for the difference in energy between the levels having quantum numbers n(initial) to n(final) is:
According to Planks theory:
E = hv
where, v is the frequency
Also,
Frequency×Wavelength = Speed of light
So,
Also, using energy from above formula as:
For longest wavelength ni = 1 and nf = 2
m= mass of the electron = 9.1 ×10⁻³¹kg
c = 3×10⁸m/s
h = 6.625×10⁻³⁴J.sec
<u>Longest wavelength = 1.2703×10⁻⁷ m</u>
For second longest wavelength ni = 1 and nf = 3
<u>Second longest wavelength = 4.7636×10⁻⁸ m</u>
For third longest wavelength ni = 1 and nf = 4
<u>Third longest wavelength = 2.5406×10⁻⁸ m</u>
Answer:
The peak value of the electric field is 489.64 V/m
Explanation:
Given;
power of the laser, P = 1.0 mW = 1 x 10⁻³ W
Radius of the beam, R = 1.0 mm = 1 x 10⁻³ m
Area of the beam = πr² = π(1 x 10⁻³ )² = 3.142 x 10⁻⁶ m²
The average intensity of the light = P / A
The average intensity of the light = ( 1 x 10⁻³) / (3.142 x 10⁻⁶)
The average intensity of the light = 318.27 W/m²
The peak value of the electric field is given by;
Therefore, the peak value of the electric field is 489.64 V/m.