The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

6 0

3 years ago

A hard drive disk rotates at 7200 rpm. The disk has a diameter of 5.1 in (13 cm). What is the speed of a point 6.0 cm from the c

ExtremeBDS [4]

Answer:

The speed will be "3.4×10⁴ m/s²".

Explanation:

The given values are:

Angular speed,

w = 7200 rpm

i.e.,

= $7200 \times \frac{2 \pi}{60}$

= $753.6 \ rad/s$

Speed from the center,

r = 6.0 cm

As we know,

⇒ Linear speed, $v=wr$

On putting the estimated values, we get

$=753.6\times 0.06$

$=45.216 \ m$

Now,

Acceleration on disk will be:

⇒ $a=\frac{v^2}{r}$

$=34074 \ m/s^2$

$=3.4\times 10^4 \ m/s^2$

3 0

3 years ago

Solve for v<br> when<br> d = 10 and<br> t=5

VashaNatasha [74]

Answer:

asfsdfasasfsda

Explanation:

7 0

3 years ago

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