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Kryger [21]
3 years ago
13

At is the slope of a line that is perpendicular to the line y = -x +5?

Mathematics
2 answers:
GaryK [48]3 years ago
5 0

Answer:

m = 1    (The slope of the line perpendicular to y = -x + 5 is supposed to be 1.)

Step-by-step explanation:

The slope of a line that is perpendicular to another line is: -(m^-^1), where m is the slope of the line.

The slope of a line perpendicular to the line y = -x + 5 will be:

m = -( -1^-^1)

m = 1

ser-zykov [4K]3 years ago
4 0

Answer:

2 (D)

Step-by-step explanation:

This is a Linear Equation. This equation will show you the y intercept, and slope of a line. In the equation shown, -1 is the coefficient of x, therefore the starting line has a slope of -1. This means that the perpendicular line should have a positive slope, because they must intersect. If it was negative it would become more or less parallel to the original line. This eliminates answers A and B. If C was chosen, the two lines would intersect but they would not be perpendicular. This means the answer is B.

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Which of the following data is used to determine credit scores? A. who stays with you at your current residence B. the location
dusya [7]

Answer:

The correct option is the length of stay at your current residence.

Step-by-step explanation:

We have been asked that which data is used to determine credit scores.

The correct option is the length of stay at your current residence.

This question is used to determine credit scores. This helps the lender to look up information about your history of payments. When a lender asks this question they are able to determine how long you typically stay in one place, and look up bills at that residence to make sure they are paid on time before giving out a loan. They can also use this information to determine a credit score based on what is being paid on time, late or not at all...

8 0
3 years ago
Question in attachment
sdas [7]

Answer:

a₁ = 6

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1}

where a₁ is the first term and r the common ratio

Here S_{8} = 1530 and r = 2, thus

\frac{a_{1}(2^{8}-1)  }{2-1} = 1530 , that is

a₁ (256 - 1) = 1530

255a₁ = 1530 ( divide both sides by 255 )

a₁ = 6

8 0
3 years ago
7+ X -9= -15 solve the equation
Aleksandr-060686 [28]
I believe the answer is x=24
6 0
3 years ago
Read 2 more answers
What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

3 0
2 years ago
3600 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 25 years, to the
Mnenie [13.5K]
Assuming the interest is simple interest, as opposed to compound interest,

\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3600\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years\to &25
\end{cases}
\\\\\\
A=3600(1+0.09\cdot 25)\implies 3600(3.25)
3 0
2 years ago
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