Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 665.9 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
1 answer:
Answer:
ΔH of reaction is -856 kJ/mol
Explanation:
The property ΔH is property which can be added to find the net change in enthalpy of reaction.
ΔH of first reaction is -665.9 kJ/mol
ΔH of second reaction is 190.1 kJ/mol
carefully looking at the third equation,
it is first reaction - second reaction.
thus, by Hess's law,
<em>Hess's Law of Constant Heat Summation (or just Hess's Law) states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.</em>
ΔH of third reaction is =
ΔH = -856 kJ/mol
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The balanced chemical reaction is :
Number of moles of Na, .
Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.
So, number of moles of oxygen are :
So, amount of oxygen required is :
Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.