Answer:the suns family is stars think about how many stars are in the sky there are billons and more billions
Explanation:
Answer:
The balanced chemical equation: 2 Al + 3Cl2→ 2 AlCl3
Mole-mole relationship: 2 moles Al + 3 moles Cl2→ 2 moles AlCl3
Given: 0.600 moleCl2; 0.500 mole Al
Required: Excess reactant___; Number of moles of AlCl3 produced__
Solution: Use dimensional analysis using the mole-mole rel
0.600 mole Cl2 * 2 moles Al/3 moles Cl2 = 0.4 mole Al
0.5 mole Al* 3 moles Cl2/2 moles Al = 0.75 mole Cl2
Based on the given:
0.6mole Cl2 + 0.4 mole Al ( this is possible based on the given)
0.5mole Al + 0.75 mole Cl2 (this is not possible because the given is only 0.600 mole of Cl 2)
Answer: Excess reactant is Al; Limiting reactant is Cl2
The amount of AlCl3 produced = 0.6 mole Cl2 + 0.4 mole Al = 1.0 mole AlCl3
Answer: The mass of 
and 
produced are 336.6 g and 183.6 g respectively.
Explanation:
The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.
Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.
a) 1 mol of propane produces = 3 moles of
Thus 2.55 mol of propane produces = ![\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B1%7D%5Ctimes%202.55%3D7.65%20moles%20of%20%5Btex%5DCO_2)
mass of 
b) 1 mol of propane produces = 4 moles of
Thus 2.55 mol of propane produces = ![\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B1%7D%5Ctimes%202.55%3D10.2%20moles%20of%20%5Btex%5DH_2O)
mass of 
The mass of and produced are 336.6 g and 183.6 g respectively.
Answer:
2311.2 cal
Explanation:
540 cal / g * 4.28 g = 2311.2 cal
