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just olya [345]
3 years ago
7

Silicon has a relatively large latent heat of vaporization of 12800 J/g. This indicates that silicon has:

Chemistry
1 answer:
beks73 [17]3 years ago
3 0
I believe it means that it takes a lot of heat in joules to make silicon vaporize so it stays solid until a great deal of heat has been added. By comparison, water has a latent heat of about 2260 joules per gram so vaporizes much more readily than silicon.
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7 0
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An atom that normally has __________ electrons in its outer (valence) shell tends not to form chemical bonds with other atoms.
goblinko [34]
8 valence shell electrons.
5 0
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In a chemical reaction how does the mass of the products compare with the mass of the reaction a greater thenb less thenc equal
Neko [114]
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5 0
3 years ago
What is the energy change if 84.0 g of calcium oxide (CaO) reacts with excess water in the following reaction?
pochemuha
   The energy change  if 84.0 g   of CaO  react  with  excess  water is  98KJ of heat is released.

calculation
heat  =  number of moles  x  delta H

delta H = - 65.2  Kj/mol

first find the number of  moles  of  CaO reacted

moles = mass/molar mass
the molar mass  of CaO =  40 +  16=  56 g/mol
mass = 84 g
moles therefore = 84 g/56 g/mol =1.5 moles

Heat is therefore =  1.5 moles  x -65.2 = - 97.8 Kj = -98 Kj

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6 0
3 years ago
In the reaction FeCl2 + 2NaOH -&gt;Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of Na0H, how many moles of NaOH
pogonyaev

Answer : The correct option is, (B) 6 mole

Explanation :

Given moles of FeCl_2 = 6 moles

Given moles of NaOH = 6 moles

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl

From the given balanced reaction, we conclude that

As, 1 moles of FeCl_2 react with 2 moles of NaOH

So, 6 moles of FeCl_2 react with \frac{2}{1}\times 6=12 moles of NaOH

From this we conclude that, FeCl_2 is an excess reagent and NaOH is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.

Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH

The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles

Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles

4 0
3 years ago
Read 2 more answers
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