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3 years ago

12

Some friends made a salad for a party. there were 28 people at the party including the friends. they bought enough cherry tomato

es for everyone to get 3 cherry tomatoes each. how many charry tomatoes did the friends buy?

1 answer:

zubka84 [21]3 years ago

8 0

Just do 28 times 3 and you will get 84 to check this just divide 84 to 28.....

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Plsss help me I don’t understand!!

inna [77]

Answer:

11

Step-by-step explanation:

in the "score" section all you do is add all them up. And because there is a negative for ALL the numbers, all you do is add a negative after you add all the SCORES

6 0

3 years ago

In parallelogram IFGH, mF = (x + 20° and mi<br> (4x – 10)<br> Find the value of x.

sveta [45]

Answer:

x = 34

Step-by-step explanation:

4x - 10 + x + 20 = 180

5x + 10 = 180

5x = 170

x = 34

6 0

3 years ago

For which value of x does f(x) = 2

laila [671]

Answer:

<h2>x = -4</h2>

Step-by-step explanation:

<em>Look a the picture</em>.

Draw the horizontal line <em>y = 2</em>.

Common point: (-4, 2).

Conclusion: f(x) = 2 → x = -4

8 0

2 years ago

Only need number 15<br><br> ugh i’m stupid

frutty [35]

Yes because 10^2+10^2=200
If you multiply a square root by itself it removes the root. Therefore making the statement 100+100=200; True

3 0

3 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$

$\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}$

$D\frac{dD}{dt} = x\frac{dx}{dt}$ (3)

We have that D is:

$D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63$

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

$\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s$

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0

2 years ago

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