La radiación alfa consiste en núcleos de helio-4 (4He) y es detenida fácilmente por una hoja de papel. La radiación beta, que consiste en electrones, es detenida por una placa de aluminio. La radiación gamma es finalmente absorbida cuando penetra en un material denso.
Answer:
The right answer is "58.3%".
Explanation:
The given values are:
Mass of lithium carbonate,
= 700 mg
i.e.,
= 0.7 g
Mass of tablet,
= 1.20 g
Now,
The percentage of active ingredient will be:
= 
On substituting the given values, we get
= 
= 
= 
%
84.24 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂O → 2 H₂ + O₂
Now we calculate the number of moles of products.
number of moles = mass / molar weight
number of moles of H₂ = 50 / 2 = 25 moles
number of moles of O₂ = 75 / 32 = 2.34 moles
We see from the chemical reaction that for every 2 moles of H₂ produced there are 1 mole of O₂ produces for every 25 moles of H₂ produced there are 12.5 moles of O₂ but we only have 2.35 moles of O₂ available. The O₂ will be the limiting quantity from which we devise the following reasoning:
if 2 moles of H₂O produces 1 mole of O₂
then X moles of H₂O produces 2.34 mole of O₂
X = (2 × 2.34) / 1 = 4.68 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 4.68 × 18 = 84.24 g
Learn more about:
limiting reactant
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Answer:
Prompt Neutrons
Explanation:
Principle. Using uranium-235 as an example, this nucleus absorbs thermal neutrons, and the immediate mass products of a fission event are two large fission fragments, which are remnants of the formed uranium-236 nucleus. These fragments emit two or three free neutrons (2.5 on average), called prompt neutrons.
<span>Kp is the equilibrium pressure constant calculated from the partial pressures of a reaction equation.
Kp =[pCF4]*[p CO2] / [p COF2]^2 = 2.2 x 10^6
When the mole fraction gets doubled we have
Kp = [pCO2]^2*[pCF4]^2 / [pCOF2]^4
Kp = [[pCF4]*[p CO2] / [p COF2]^2] * 2
Kp = (2.2 * 10^6) * 2
Kp = 4.8 * 10^12</span>
