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Step2247 [10]
4 years ago
14

What is the lift (in newtons) due to Bernoulli's principle on a wing of area 96 m2m2 if the air passes over the top and bottom s

urfaces at speeds of 270 m/sm/s and 150 m/sm/s, respectively?
Physics
1 answer:
egoroff_w [7]4 years ago
5 0

Answer:

F_{lift}=2.42*10^{9} N

Explanation:

Apply Bernoulli's principle

p_{b}+1/2pv_{b}^{2} =p_{t}+1/2pv_{t}^{2} \\p_{b}-p_{t}= 1/2pv_{t}^{2}-1/2pv_{b}^{2}\\p_{b}-p_{t}= 1/2(1.00*10^{3}  kgm^{-3} )(270m/s^{2} )-1/2(1.00*10^{3}kgm^{-3} )(150m/s^{2} )\\p_{b}-p_{t}=2.52*10^{7}N/m^{2}\\  F_{lift}=2.52*10^{7}N/m^{2}*96m^{2} \\ F_{lift}=2.42*10^{9} N

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