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3 years ago

Select all that apply: Select the benefits of sexual reproduction.

Chemistry

1 answer:

malfutka [58]3 years ago

6 0

Sexual reproduction promotes adaptations, increases genetic diversity, and increases chances of survival.

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What is the wavelength in nm of a light whose first order bright band forms a

miskamm [114]

Answer:

714 nm

Explanation:

Using the equation: nλ=d<em>sin</em>θ

where

n= order of maximum

λ= wavelength

d= distance between lines on diffraction grating

θ= angle

n is 1 because the problem states the light forms 1st order bright band

λ is unknown

d= $\frac{1}{700,000}$ or 0.0000014 (meters)

sin(30)= 0.5

(1)λ=(0.0000014)(0.5)

=0.000000714m or 714 nm

3 0

2 years ago

A ____ is the remains of a once-living organism found in layers of rocks, ice, or amber

aksik [14]

Answer:

fossil

Explanation:

the dead organism is called a fossil i think

8 0

2 years ago

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A crime-scene is roped off with yellow tape. The rectangular area is 5.6 meters long 10.75 meters wide. What is the area of the

maksim [4K]

The area is 60.2, to find area it's length times width.

7 0

3 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

$PCl_3,p_1'=6.798 Torr$

$Cl_2,p_2'=26.398 Torr$

$PCl_5,p_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=p_1=13.2 Torr$

Partial pressure of the $Cl_2=p_2=13.2 Torr$

Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{p_1}{p_1\times p_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=p_1'+p_2'+p_3'$

$263.0Torr=13.2 Torr+p_2'+217.0 Torr$

$p_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

$p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

6 0

2 years ago

The balanced equation for photosynthesis is shown below.

klio [65]

The true answer is: It's conserved because the total number of H atoms on each side is 12.
the first two answer is wrong because it's conserved not as mentioned, It's not conserved.

and the last one also wrong because the total number of O atoms are equal at the two sides but not equal 2.

3 0

2 years ago

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