Answer:
The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.
Explanation:
Given;
length of the straight wire, L = 0.56 m
conventional current, I = 0.4 A
distance of magnetic field from the wire, r = 2.6 cm = 0.026 m
To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;
Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.
<span>a = (v2 - v1)/t= acceleration formula
a = (70 - 0)/7
a = 10 km/hr/sec
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It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>
Answer:
The time after which the two stones meet is tₓ = 4 s
Explanation:
Given data,
The height of the building, h = 200 m
The velocity of the stone thrown from foot of the building, U = 50 m/s
Using the II equation of motion
S = ut + ½ gt²
Let tₓ be the time where the two stones meet and x be the distance covered from the top of the building
The equation for the stone dropped from top of the building becomes
x = 0 + ½ gtₓ²
The equation for the stone thrown from the base becomes
S - x = U tₓ - ½ gtₓ² (∵ the motion of the stone is in opposite direction)
Adding these two equations,
x + (S - x) = U tₓ
S = U tₓ
200 = 50 tₓ
∴ tₓ = 4 s
Hence, the time after which the two stones meet is tₓ = 4 s
