The Speed of a moving vehicle can be measured. The average time it will taken too cover both distance are shown below;
The average travel times traveled are :
0.25 meters = 2.23 seconds
0.50 meters = 3.13 seconds
Therefore, the Average travel time to cover 0.25 meters is:
(Trial 1 + Trial 2 + Trial 3) ÷ 3
(2.24 + 2.21 + 2.23) / 3 = 6.68 = 2.2266 = 2.23 seconds ( approximated to 2 decimal places).
Therefore, the Average travel time to cover 0.50 meters is
(Trial 1 + Trial 2 + Trial 3) ÷ 3
(3.16 + 3.08 + 3.15) / 3 = 9.39 ÷ 3 = 3.13 seconds
Conclusively, the average time taken to cover 0.25 and 0.50 meters is said to be 2.23 and 3.13 seconds for the both..
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The entire motion of an object, regardless of direction.
In physics, motion is that the phenomenon in which an object changes its position with respect to time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and frame of regard to an observer and measuring the change in position of the body relative to that frame with change in time. The branch of physics describing the motion of objects without regard to their cause is called kinematics, while the branch studying forces and their effect on motion are named dynamics.
If an object isn't changing relative to a given frame of reference, the thing is said to be at rest, motionless, immobile, stationary, or to possess a constant or time-invariant position with reference to its surroundings. Modern physics holds that, as there's no absolute frame of reference, Newton's concept of absolute motion can't be determined
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The video called “SOH CAH TOA: how to solve a right triangle.”
This is explained very well. Make sure you write down the “equations” of SOH CAH and TOA. It helps a lot to be able to go back and plug in from the equation.
Transferring its energy to its surroundings.
Answer:
The hydro static force on the back of the dam is 
Explanation:
Given that,
Width b= 1000 m
Depth d= 200 m
We need to calculate the average pressure
Using formula of average pressure

Put the value into the formula


We need to calculate the hydro static force on the back of the dam
Using formula of force

Put the value into the formula


Hence, The hydro static force on the back of the dam is 