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melamori03 [73]
3 years ago
14

Which of the following selections completes the given radioactive decay? A). Alpha particle B). Gamma radiation. C). Positron. D

). Neutron. E). Beta particle.

Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

gamma radiation

is which I think

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Photo shows all! Need help ASAP! Will mark brainlist
Goryan [66]

Answer:

The student is getting different info bc the students probable keeping track of the distance instead of the displacement.

Explanation:

5 0
3 years ago
A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.
dsp73

Answer:

<h3>0.445</h3>

Explanation:

In friction, the coefficient of friction formula is expressed as;

\mu = \frac{F_f}{R}

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta

Given

θ = 24°

\mu = tan 24^0\\\mu = 0.445\\

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

3 0
3 years ago
A car moving around a circular track with constant speed (Select all that apply.) has an acceleration with a direction that cann
BARSIC [14]

Answer:

Explanation:

Has an acceleration directed towards center of its path

5 0
3 years ago
Has human activity cause the world climate to change over the past hundred years
algol13

Yes, it did help to change the world climate

for example by the Carbon Dioxide released from factories, Cars and even from respiration

3 0
3 years ago
A car is traveling with a constant speed when the driver suddenly applies the brakes, giving the 14) car a deceleration of 3.50
sergij07 [2.7K]
To be able to determine the original speed of the car, we use kinematic equations to relate the acceleration, distance and the original speed of the car moving. 

First, we manipulate the one of the kinematic equations
 
v^2 = v0^2 + 2 (a) (x)  where v = 0 since the car stopped

Writing the equation in such a way that the initial velocity or v0 is written on one side of the equation,

<span>we get v0 = sqrt (2(a)(x))

Substituting the known values,

v0 = sqrt(2(3.50)(30.0))
v0 = 14.49 m/s 
</span>
Therefore, before stopping the car the original speed of the car would be 14.49 m/s
7 0
3 years ago
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