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Brrunno [24]
4 years ago
7

What does "Time (s)" represent in the graph?

Physics
2 answers:
polet [3.4K]4 years ago
5 0

Answer:

D

Explanation:

Part 1: Graphing Techniques

In Physics we use a variety of tools – including words, equations, and graphs – to make models of the motion of

objects and the interactions between objects in a system. Graphs are one of the best ways to directly visualize

the quantitative relationship between two variables – in other words, whether the variables are directly

proportional, inversely proportional, not related at all, or something else entirely.

When we construct a graph, we plot the independent variable – the variable that the experimenter controls – on

the x-axis, and the dependent variable – the variable that responds when the independent variable is changed –

on the y-axis. There are also control variables – variables that are kept constant throughout the experiment so

that they do not influence the data. So, for example, if you were trying to determine how the period of a

pendulum changes when the length of the pendulum is varied, the dependent variable would be the pendulum’s

period, and the independent variable would be the pendulum’s length. Controlled variables would include the

pendulum’s mass and the angle at which the pendulum was launched.

An appropriate graph for this experiment is shown below.

Notice that the title lists the dependent variable, which is plotted on the y-axis, first, and the independent

variable, which is plotted on the x-axis, second. The axes are correctly labeled with the appropriate units. The

graph begins at (0, 0) with no “jumps”, and increments are equally spaced.

In this experiment, we can clearly see that as the length of the pendulum increases, the period also increases, but

are the variables directly proportional? In other words, can we write an equation for the relationship in the form

y = mx + b? Excel will draw a trend line for a graph that can help us to determine this.

0

1

2

3

4

5

6

0 1 2 3 4 5 6 7

P

e

r

i

o

d

( s)

Length (m)

Period vs. Length of a Pendulum

While the graph appears to be somewhat linear, we can see a few problems – first, the majority of the points do

not fall on the line; second, the line does not cross the y-axis at zero, and we would expect it to – after all, a

pendulum with a length very close to zero meters should have a period very close to zero seconds. To

determine the correct relationship between the variables, we will have to linearize the graph.

jenyasd209 [6]4 years ago
3 0

Answer:

D

Explanation:

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A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is n
Scilla [17]

Answer:

Explanation:

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29  - 7.82 )

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8 0
4 years ago
A 1.20-m cylindrical rod of diameter 0.570 cm is connected to a power supply that maintains a constant potential difference of 1
nasty-shy [4]

(a) 1.72\cdot 10^{-5} \Omega m

The resistance of the rod is given by:

R=\rho \frac{L}{A} (1)

where

\rho is the material resistivity

L = 1.20 m is the length of the rod

A is the cross-sectional area

The radius of the rod is half the diameter: r=0.570 cm/2=0.285 cm=2.85\cdot 10^{-3} m, so the cross-sectional area is

A=\pi r^2=\pi (2.85\cdot 10^{-3} m)^2=2.55\cdot 10^{-5} m^2

The resistance at 20°C can be found by using Ohm's law. In fact, we know:

- The voltage at this temperature is V = 15.0 V

- The current at this temperature is I = 18.6 A

So, the resistance is

R=\frac{V}{I}=\frac{15.0 V}{18.6 A}=0.81 \Omega

And now we can re-arrange the eq.(1) to solve for the resistivity:

\rho=\frac{RA}{L}=\frac{(0.81 \Omega)(2.55\cdot 10^{-5} m^2)}{1.20 m}=1.72\cdot 10^{-5} \Omega m

(b) 8.57\cdot 10^{-4} /{\circ}C

First of all, let's find the new resistance of the wire at 92.0°C. In this case, the current is

I = 17.5 A

So the resistance is

R=\frac{V}{I}=\frac{15.0 V}{17.5 A}=0.86 \Omega

The equation that gives the change in resistance as a function of the temperature is

R(T)=R_0 (1+\alpha(T-T_0))

where

R(T)=0.86 \Omega is the resistance at the new temperature (92.0°C)

R_0=0.81 \Omega is the resistance at the original temperature (20.0°C)

\alpha is the temperature coefficient of resistivity

T=92^{\circ}C

T_0 = 20^{\circ}

Solving the formula for \alpha, we find

\alpha=\frac{\frac{R(T)}{R_0}-1}{T-T_0}=\frac{\frac{0.86 \Omega}{0.81 \Omega}-1}{92C-20C}=8.57\cdot 10^{-4} /{\circ}C

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3 years ago
The cricket player while catches the ball wears gloves and why​
gregori [183]

Answer:

the ball is travelling very fast and the player can get injured if he doesn't wear gloves

Explanation:

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Does the accuracy of a measurement made always depend on the precision of the instrument used to make the measurement? Why or Wh
mina [271]

Answer:

B

Explanation:

YOUR MUM NOOB SORRY MY MAD THE ANSWER WILL BE B BECAUSE B IS THE BEST YAY.

8 0
3 years ago
Drag each label to the correct location on the image
umka2103 [35]

Answer:

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