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Brrunno [24]
4 years ago
7

What does "Time (s)" represent in the graph?

Physics
2 answers:
polet [3.4K]4 years ago
5 0

Answer:

D

Explanation:

Part 1: Graphing Techniques

In Physics we use a variety of tools – including words, equations, and graphs – to make models of the motion of

objects and the interactions between objects in a system. Graphs are one of the best ways to directly visualize

the quantitative relationship between two variables – in other words, whether the variables are directly

proportional, inversely proportional, not related at all, or something else entirely.

When we construct a graph, we plot the independent variable – the variable that the experimenter controls – on

the x-axis, and the dependent variable – the variable that responds when the independent variable is changed –

on the y-axis. There are also control variables – variables that are kept constant throughout the experiment so

that they do not influence the data. So, for example, if you were trying to determine how the period of a

pendulum changes when the length of the pendulum is varied, the dependent variable would be the pendulum’s

period, and the independent variable would be the pendulum’s length. Controlled variables would include the

pendulum’s mass and the angle at which the pendulum was launched.

An appropriate graph for this experiment is shown below.

Notice that the title lists the dependent variable, which is plotted on the y-axis, first, and the independent

variable, which is plotted on the x-axis, second. The axes are correctly labeled with the appropriate units. The

graph begins at (0, 0) with no “jumps”, and increments are equally spaced.

In this experiment, we can clearly see that as the length of the pendulum increases, the period also increases, but

are the variables directly proportional? In other words, can we write an equation for the relationship in the form

y = mx + b? Excel will draw a trend line for a graph that can help us to determine this.

0

1

2

3

4

5

6

0 1 2 3 4 5 6 7

P

e

r

i

o

d

( s)

Length (m)

Period vs. Length of a Pendulum

While the graph appears to be somewhat linear, we can see a few problems – first, the majority of the points do

not fall on the line; second, the line does not cross the y-axis at zero, and we would expect it to – after all, a

pendulum with a length very close to zero meters should have a period very close to zero seconds. To

determine the correct relationship between the variables, we will have to linearize the graph.

jenyasd209 [6]4 years ago
3 0

Answer:

D

Explanation:

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lina2011 [118]
Is there a multiple choice?
4 0
4 years ago
Find the perimeter of the rectangle if each block represents one foot(show your calculation)
iren2701 [21]

I'm pretty sure that the "block" of which you speak is one in a pattern
of them that covers the drawing you have of the rectangle, and now
I need to explain something to you: 

The REASON for printing that drawing next to the question that you
partially copied is that the drawing has information that's needed to
answer the question with, and rather than repeat all that information
in the question, it just says "LOOK AT THE DRAWING !"

In fact, the whole point of the question may not be just to remind you of
what "perimeter" means.  It's more likely that the purpose of this problem
is to make you pick the information you need off of a drawing. 

Either way, if you'll kind of "read between the lines" of the part of the
question that you DID copy, it should be pretty obvious to you that nobody's
going nowhere in the direction of a solution without SEEing the drawing. 

So my bottom-line conclusion regarding a solution for this problem is: 
Not possible with the given information.

4 0
3 years ago
A)If the rms value of the electric field in an electromagnetic wave is doubled, by what factor does the rms value of the magneti
Ghella [55]

A) The magnetic field doubles as well

The relationship between rms value of the electric field and rms value of the magnetic field for an electromagnetic wave is the following:

E_{rms}=cB_{rms}

where

E_rms is the magnitude of the electric field

c is the speed of light

B_rms is the magnitude of the magnetic field

From the equation, we see that the electric field and the magnetic field are directly proportional: therefore, if the rms value of the electric field is doubled, then the rms value of the magnetic field will double as well.

B) The intensity will quadruple

The intensity of an electromagnetic wave is given by

I=\frac{1}{2}c\epsilon_0 E_0^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E_0 is the peak intensity of the electric field

The rms value of the electric field is related to the peak value by

E_{rms}=\frac{E_0}{\sqrt{2}}

So we can rewrite the equation for the intensity as

I=c\epsilon_0 E_{rms}^2

we see that the intensity is proportional to the square of the rms value of the electric field: therefore, if the rms value of the electric field is doubled, the average intensity of the wave will quadruple.

7 0
3 years ago
Can I please have help
NeTakaya

Answer:

it will usually increase

Explanation:

potato

6 0
3 years ago
The speed of S-waves is what percent of that of P-Waves?<br><br><br><br><br><br><br> Help plz
zlopas [31]

Answer:

For the distance range 50 to 500 km, the S-waves travel about 3.45 km/s and the P-waves around 8 km/s.

hope it helps.

3 0
3 years ago
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