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4 years ago

What does "Time (s)" represent in the graph?

Physics

2 answers:

polet [3.4K]4 years ago

5 0

Answer:

Explanation:

Part 1: Graphing Techniques

In Physics we use a variety of tools – including words, equations, and graphs – to make models of the motion of

objects and the interactions between objects in a system. Graphs are one of the best ways to directly visualize

the quantitative relationship between two variables – in other words, whether the variables are directly

proportional, inversely proportional, not related at all, or something else entirely.

When we construct a graph, we plot the independent variable – the variable that the experimenter controls – on

the x-axis, and the dependent variable – the variable that responds when the independent variable is changed –

on the y-axis. There are also control variables – variables that are kept constant throughout the experiment so

that they do not influence the data. So, for example, if you were trying to determine how the period of a

pendulum changes when the length of the pendulum is varied, the dependent variable would be the pendulum’s

period, and the independent variable would be the pendulum’s length. Controlled variables would include the

pendulum’s mass and the angle at which the pendulum was launched.

An appropriate graph for this experiment is shown below.

Notice that the title lists the dependent variable, which is plotted on the y-axis, first, and the independent

variable, which is plotted on the x-axis, second. The axes are correctly labeled with the appropriate units. The

graph begins at (0, 0) with no “jumps”, and increments are equally spaced.

In this experiment, we can clearly see that as the length of the pendulum increases, the period also increases, but

are the variables directly proportional? In other words, can we write an equation for the relationship in the form

y = mx + b? Excel will draw a trend line for a graph that can help us to determine this.

0 1 2 3 4 5 6 7

( s)

Length (m)

Period vs. Length of a Pendulum

While the graph appears to be somewhat linear, we can see a few problems – first, the majority of the points do

not fall on the line; second, the line does not cross the y-axis at zero, and we would expect it to – after all, a

pendulum with a length very close to zero meters should have a period very close to zero seconds. To

determine the correct relationship between the variables, we will have to linearize the graph.

jenyasd209 [6]4 years ago

3 0

Answer:

Explanation:

You might be interested in

The distance from earth to mars ranges between 780,000,000 km and 380,000,000 km depending on the time of the year. The speed of

ivann1987 [24]

Answer:

The minimum time, t = 21.11 m

Explanation:

Given,

The maximum distance between the Earth and Mars, d = 780,000,000 km

The speed of the light, c = 300,000 km/s

The distance and speed of the object is related using the formula,

v = d / t

t = d / v

The minimum time it takes for data transmission is when the distance between the Mars and the Earth is at minimum.

Therefore,

t = 380,000,000 km / 300,000 km/s

= 1266.67 s

= 21.11 minutes

Hence, the minimum time it takes for data transmitted by the Mars Surveyor to reach earth, t = 21.11 minutes

6 0

3 years ago

a bal is launched upward with a velocity of v0 from the edge of a cliff of height D. it reaches a maximum height of H above its

lilavasa [31]

Answer:

D/H =15

Explanation:

We can find first the peak height H, taking into consideration, that at the maximum height, the ball will reach momentarily to a stop.
At this point, we can find the value of H, applying the following kinematic equation:

$v_{f} ^{2} -v_{0} ^{2} = 2* g* H (1)$

If vf=0, if we assume that the positive direction is upwards, we can find the value of H as follows:

$H = \frac{v_{0} ^{2} }{2*g} (2)$

We can use the same equation, to find the value of D, as follows:

$v_{f} ^{2} -v_{1} ^{2} = 2* g* D (3)$

In order to find v₁, we can use the same kinematic equation that we used to get H, but now, we know that v₀ = 0.
When we replace these values in (1), we find that v₁ = -v₀.
Replacing in (3), we have:

$(4*v_{0})^{2} - (-v_{0}) ^{2} = 2* g* D\\ \\ 15*v_{0}^{2} = 2*g*D$

Solving for D:

$D = \frac{15*v_{0} ^{2} }{2*g}$

From (2) we know that H can be expressed as follows:

$H = \frac{v_{0} ^{2} }{2*g}$

⇒ D = 15 * H

$\frac{D}{H} = 15$

3 0

3 years ago

A parallel plate capacitor with air between the plates has a potential difference of 71.0 V. Determine the potential difference

Gwar [14]

Answer:

15.8 V

Explanation:

The relationship between capacitance and potential difference across a capacitor is:

$q=CV$

where

q is the charge stored on the capacitor

C is the capacitance

V is the potential difference

Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.

Later, a dielectric material is inserted between the two plates, so the capacitance changes according to

$C'=kC$

where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,

$q=C'V'$

So we can combine the two equations:

$CV=CV'\\CV=(kC)V'\\V'=\frac{V}{k}$

and since we have

V = 71.0 V

k = 4.50

We find the new potential difference:

$V'=\frac{71.0}{4.50}=15.8 V$

6 0

3 years ago

Use wave equation calculate the speed of sound in the air if frequency of 110 hz has a wave length of 3 m

kirill115 [55]

Answer = 330 m/s

The wave equation is as follows:

Wave speed = wavelength x frequency

The known values are:
Wavelength = 3m
Frequency = 110 Hz

Substitute the known values into the wave equation to find the wave speed.

Wave speed = 3 x 110

Wave speed = 330 m/s

8 0

2 years ago

"A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a s

Tamiku [17]

Answer:

The film thickness is 4.32 * 10^-6 m

Explanation:

Here in this question, we are interested in calculating the thickness of the film.

Mathematically;

The number of fringes shifted when we insert a film of refractive index n and thickness L in the Michelson Interferometer is given as;

ΔN = (2L/λ) (n-1)

where λ is the wavelength of the light used

Let’s make L the subject of the formula

(λ * ΔN)/2(n-1) = L

From the question ΔN = 8 , λ = 540 nm, n = 1.5

Plugging these values, we have

L = ((540 * 10^-9 * 8)/2(1.5-1) = (4320 * 10^-9)/1 = 4.32 * 10^-6 m

6 0

3 years ago