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Brrunno [24]
3 years ago
7

What does "Time (s)" represent in the graph?

Physics
2 answers:
polet [3.4K]3 years ago
5 0

Answer:

D

Explanation:

Part 1: Graphing Techniques

In Physics we use a variety of tools – including words, equations, and graphs – to make models of the motion of

objects and the interactions between objects in a system. Graphs are one of the best ways to directly visualize

the quantitative relationship between two variables – in other words, whether the variables are directly

proportional, inversely proportional, not related at all, or something else entirely.

When we construct a graph, we plot the independent variable – the variable that the experimenter controls – on

the x-axis, and the dependent variable – the variable that responds when the independent variable is changed –

on the y-axis. There are also control variables – variables that are kept constant throughout the experiment so

that they do not influence the data. So, for example, if you were trying to determine how the period of a

pendulum changes when the length of the pendulum is varied, the dependent variable would be the pendulum’s

period, and the independent variable would be the pendulum’s length. Controlled variables would include the

pendulum’s mass and the angle at which the pendulum was launched.

An appropriate graph for this experiment is shown below.

Notice that the title lists the dependent variable, which is plotted on the y-axis, first, and the independent

variable, which is plotted on the x-axis, second. The axes are correctly labeled with the appropriate units. The

graph begins at (0, 0) with no “jumps”, and increments are equally spaced.

In this experiment, we can clearly see that as the length of the pendulum increases, the period also increases, but

are the variables directly proportional? In other words, can we write an equation for the relationship in the form

y = mx + b? Excel will draw a trend line for a graph that can help us to determine this.

0

1

2

3

4

5

6

0 1 2 3 4 5 6 7

P

e

r

i

o

d

( s)

Length (m)

Period vs. Length of a Pendulum

While the graph appears to be somewhat linear, we can see a few problems – first, the majority of the points do

not fall on the line; second, the line does not cross the y-axis at zero, and we would expect it to – after all, a

pendulum with a length very close to zero meters should have a period very close to zero seconds. To

determine the correct relationship between the variables, we will have to linearize the graph.

jenyasd209 [6]3 years ago
3 0

Answer:

D

Explanation:

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attashe74 [19]

<u>Answer:</u>

The amount of the lighted side of the moon you can see is the same during "how much of the sunlit side of the moon faces Earth".

<u>Explanation:</u>

The Moon is in sequential rotation with Earth, and thus displays the Sun, the close side, always on the same side. Thanks to libration, Earth can display slightly greater than half (nearly 59 per cent) of the entire lunar surface.

The side of the Moon facing Earth is considered the near side, and the far side is called the reverse. The far side is often referred to as the "dark side" inaccurately but it is actually highlighted as often as the near side: once every 29.5 Earth days. During the New Moon the near side becomes blurred.

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When preparing to strip insulation in order to splice conductors, a person should strip the insulation back far enough so that t
Fiesta28 [93]

Answer:

Closely fits into the connector.

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A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 320 with the surface of the l
Virty [35]

Answer:

N = 337.96 N

Explanation:

∅ = 32º

F = 249 N

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N = ?

We can apply:

∑ F = 0  (↑)

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⇒  F*Sin ∅ + m*g = N

⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)

⇒  N = 337.96 N  (↑)

8 0
3 years ago
Block b rests upon a smooth surface. if the coefficients of static and kinetic friction between a and b are μs = 0.4 and μk = 0.
aliina [53]

Given

Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,

 

6 = (20 / 32.2 + 50 / 32.2)a

 

2.173a = 6

 

A = 2.76 ft/s^2

 

To check slipping occurs between block A and block B, consider block A:

P – Ff = mAaA

6 – Ff = 1.71

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And also,

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Fs = µsN

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<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2</span>

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