The mass of iron (III) oxide (Fe2O3) : 85.12 g
<h3>Further explanation</h3>
Given
3.20x10²³ formula units
Required
The mass
Solution
1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mol of Fe₂O₃ :

mass of Fe₂O₃ (MW=160 g/mol)

22) Oxygen with a -2 charge
23) Neon with a +2 charge
24) Fluorine with a -1 charge
25) Lithium with a +1 charge
Answer:
180g
Explanation:
H:1 O:16
2H2+O2 → 2H2O
2 2(16) 2(1)+(16)
32 18
Now,
32g of O → 2(18)g of H2O
160g of O → 2(18)g divides by 32g times 160g
=180g
I believe it is C but if not that A