Two forces that are not equel in size are

A ______________________ is the distance from one compression to the next compression in a longitudinal wave.

svetoff [14.1K]

Answer: D

Explanation:

8 0

2 years ago

A substance is analyzed and found to contain 85.7% carbon and 14.3% hydrogen by weight. A gaseous sample of the substance is fou

atroni [7]

Answer:

The empirical formula of the compound is CH2

Explanation:

Step 1: Data given

A substance contains 85.7 % carbon and 14.3 % hydrogen.

The substance has a density of 1.87 g/L

1 mol occupies 22.4 L

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.01 g/mol

Step 2: Calculate molar mass of the substance

Since 1 mol occupies 22.4 L;

1 mol of this substance = 1.87g/L *22.4 = 41.888 grams

This means the molar mass of the substance is 41.888 g/mol

Step 3: Calculate mass of carbon:

85.8 % is carbon

this means 41.888 * 0.858 = 35.94 grams

Step 4: Calculate moles of carbon

moles C = mass C/ Molar mass C

Moles C = 35.94 grams / 12 g/mol

Moles C = 2.995 moles

Step 5: Calculate mass of hydrogen:

14.3 % is hydrogen

this means 41.888 * 0.143 = 5.99 grams

Step 6 :Calculate moles of hydrogen

Moles H = 5.99 grams / 1.01 g/mol

Moles H = 5.93 moles

Step 7: Calculate mol ratio

Ratio C:H = 1:2

The empirical formule = CH2

Step 8: calculate molar formule

Molar mass of empirical formule = 14.02 g/mol

n = Molar mass of substance / molar mass of empirical formule

n = 41.888 / 14.02 = 3

This means we have to multiply the empirical formula by 3

3*(CH2) = C3H6

C3H6 can be propene or cyclopropane

5 0

3 years ago

The reactants of two chemical equations are listed.

Oksi-84 [34.3K]

Answer:

Equation 2, because K being more reactive, exchanges position with Pb in PbNO3.

Explanation:

3 0

3 years ago

2.Which of the alcohols listed below would you expect to react most rapidly with PBr3?A)CH3CH2CH2CH2CH2CH2OHB)(CH3CH2)2CH(OH)CH2

Gnoma [55]

Answer:

A) CH3CH2CH2CH2CH2CH2OH

Explanation:

For this question, we have the following answer options:

A) CH3CH2CH2CH2CH2CH2OH

B) (CH3CH2)2CH(OH)CH2CH3

C) (CH3CH2)2CHOHCH3

D) (CH3CH2)3COH

E) (CH3CH2)2C(CH3)OH

We have to remember the reaction mechanism of the substitution reaction with $PBr_3$ . The idea is to generate a better leaving group in order to add a "Br" atom.

The $PBr_3$ attacks the "OH" generation new a bond to P (O-P bonds are very strong), due to this new bond we will have a better leaving group that can remove the oxygen an allow the attack of the Br atom to generating a new C-Br bond. This is made by an Sn2 reaction. Therefore we will have a faster reaction with primary substrates. In this case, the only primary substrate is molecule A. So, "CH3CH2CH2CH2CH2CH2OH" will react faster.

See figure 1

I hope it helps!

7 0

3 years ago

In an oxidation–reduction reaction, what happens to the electrons in the oxidation process? A. Electrons are bonded. B. Electron

DanielleElmas [232]

Answer: C. Electrons are lost.

Explanation:

The oxidation reduction reaction is between oxidizing agent and reducing agent.

The oxidizing agent gains electrons and reduction process occurs to it, while the reducing agent losses electrons and oxidation process occurs to it.

oxidizing agent + ne → product "reduction process, gain electrons"

reducing agent → product + ne "oxidation process, loss electrons"

Thus, The right answer is: in the oxidation process, electrons are lost.

7 0

3 years ago

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