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katrin2010 [14]
3 years ago
15

Two forces that are not equel in size are

Chemistry
1 answer:
satela [25.4K]3 years ago
3 0
Balanced and Unbalanced Forces
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Identify the nonelectrolyte
pashok25 [27]

Answer: Cl2

Explanation: ionic compounds forms cations and anions in water solution.

HI is a weak acid and forms H+ and I- ions. Cl2 is dissolved slightly in water

And stays in molecule form which can not transfer charge like cations and anions.

4 0
2 years ago
Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.
Daniel [21]

Explanation:

  • We need to find the amount of carbon dioxide gas in 1.505\times 10^{23} molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains 6.022\times 10^{23} number of molecules. It means that, 6.022\times 10^{23} number of molecules present in 44 grams of carbon dioxide molecule. So,1.505\times 10^{23}  number of molecules present in :

=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}

  • Hence, 7.675 grams of carbon dioxide is present in 1.505\times 10^{23} molecules of the gas.
4 0
3 years ago
Ca+HCI—>CaCI2+H2, what is the reaction?
arsen [322]

Answer:

single replacement reaction

Explanation:

This is a kind of single replacement reaction where you switch either cations or anions. Here you switched Ca for H and produced Cacl2 and H2 gas by itself.

4 0
3 years ago
Read 2 more answers
Determine the molar solubility for Cr(OH)3 Ksp = 6.3x10^-31 ....
r-ruslan [8.4K]

asgvjitipvvkkighnnoiopouhfd

6 0
2 years ago
The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a
melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

                          (100ml - 1.468 ml)

                        = 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

          Amount of water = \frac{1.468 ml \times 23 ml}{98.532 ml}

                                       = 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

                Mg + H_{2}O \rightarrow Mg(OH)_{2}

Molar mass of Mg = 24.305 g

Molar mass of H_{2}O = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

           Amount of Mg = \frac{24.305 g \times 0.3427 ml}{18 g}  

                                    = 0.462 g

   

6 0
3 years ago
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