The jnd for a 100-gram weight, according to Weber's law will be 10 gram.
<h3>What is Weber's law?</h3>
It should be noted that Weber's law asserts that the nature of any given stimulus will always affect how change is perceived. In other words, the size, weight, importance, etc. of the prior situation and the significance of the change both influence whether a change will be observed.
In this case, it was given that the jnd for a 10-gram weight was 1 gram, therefore, the jnd for 100 gram will be;
= 100 / 10
= 10 gram
Therefore, jnd for a 100-gram weight, according to Weber's law will be 10 grams.
Learn more about weight on:
brainly.com/question/19753744
#SPJ1
Answer:
y = -19.2 sin (23.15t) cm
Explanation:
The spring mass system is an oscillatory movement that is described by the equation
y = yo cos (wt + φ)
Let's look for the terms of this equation the amplitude I
y₀ = 19.2 cm
Angular velocity is
w = √ (k / m)
w = √ (245 / 0.457
w = 23.15 rad / s
The φ phase is determined for the initial condition t = 0 s
, the velocity is negative v (0) = -vo
The speed of the equation is obtained by the derivative with respect to time
v = dy / dt
v = - y₀ w sin (wt + φ)
For t = 0
-vo = -yo w sin φ
The angular and linear velocity are related v = w r
v₀ = w r₀
v₀ = v₀ sinφ
sinφ = 1
φ = sin⁻¹ 1
φ = π / 4 rad
Let's build the equation
y = 19.2 cos (23.15 t + π/ 4)
Let's use the trigonometric ratio π/ 4 = 90º
Cos (a +90) = cos a cos90 - sin a sin sin 90 = 0 - sin a
y = -19.2 sin (23.15t) cm
<h2>
Time needed is 2545.45 seconds.</h2>
Explanation:
We know equation for power
Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.
So
Work = 5.6 × 10⁷ J
Power = 22 kW = 22 x 10³ W
Substituting
Time needed is 2545.45 seconds.
your answer would be The one in the top right corner that looks a bit like this..
Answer:
<em>58,800Joules</em>
Explanation:
The energy lost is equal to the workdone by the car as it skids.
Workdone = Force * Distance
Given
Force = 8000N
Get the distance using the equation of motion
v² = u² - 2gS
0² = 12² - 2(9.8)S
-12² = - 2(9.8)S
-144 = -19.6S
S = 144/19.6
S = 7.35m
Calculate the required energy
Workdone = 8000 * 7.35
Workdone = 58,800Joules
<em>Hence the energy lost due to friction is 58,800Joules</em>
