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3 years ago

Please help With the question! Ill mark brainliest for whoever answers First.

Physics

2 answers:

IgorC [24]3 years ago

8 0

Answer: Asteroids

Explanation: space rubble

IntroductionAsteroids, sometimes called minor planets, are rocky remnants left over from the early formation of our solar system about 4.6 billion years ago. Most of this ancient space rubble can be found orbiting the sun between Mars and Jupiter within the main asteroid belt.

kodGreya [7K]3 years ago

6 0

I think it’s Asteroid

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Enrique is given information about a satellite orbiting Earth. R = 3. 8 Ă— 108 m T = 18 days In order to calculate the tangentia

NISA [10]

The first step that Enrique must take in order to calculate the tangential speed of the satellite is to convert the period from days to seconds.

We know that the SI unit of speed is meter per second and now, we with to obtain the tangential speed of the satellite.

Since the period is given in days, the first step is to convert the period from days to seconds.

Learn more: brainly.com/question/17638582

6 0

3 years ago

A solid, horizontal cylinder of mass 10.6 kg and radius 1.00 m rotates with an angular speed of 8.00 rad/s about a fixed vertica

n200080 [17]

Answer:

The final angular speed is 7.71 rad/s

Explanation:

Given

Cylinder mass, M = 10.6 kg

Cylinder radius, R = 1.00 m

Angular speed, w = 8.00 rad/s.

Mass of putty, m = 0.250-kg

Radius, r = 0.900 m

First, we set up an expression for the initial and final angular momentum of the system.

The moment of inertia of the cylinder is given as I = ½MR²

While the moment of inertia if the putty is mr².

Initial Momentum of the system = Initial momentum of the cylinder =

Li = Iw --- Substitute ½MR² for I

Li = ½MR²w

Substituton

Li = ½ * 10.6 * 1² * 8

Li = 42.4kgm²/s

Calculating the final momentum of the system.

First we calculate the final momentum of the cylinder

Li = Iw --- Substitute ½MR² for I

Li = ½MR²wf where wf = final angular speed

Substituton

Li = ½ * 10.6 * 1² wf

Li = 5.3w kgm²/s

Then we calculate the final momentum of the putty

Final Momentum of the putty =

L2 = Iwf --- Substitute mr² for I;

L2 = mr²wf --- By Substituton

L2 = 0.25 * 0.9² * wf

L2 = 0.2025wf kgm²/s

Final momentum = Li + L2

Lf = (5.3wf + 0.2025wf) kgm²/s

Lf = 5.5025wf kgm²/s

By conservation of momentum

Li = Lf

Where Li = 42.4kgm²/s and Lf = 5.5025wf kgm²/s

So, we have

5.5025wf kgm²/s = 42.4kgm²/s --- make wf the subject of formula

wf = 42.4/5.5025

wf = 7.71 rad/s

Hence, the final angular speed is 7.71 rad/s

5 0

3 years ago

A single force acts on a 2.0 kg particle-like object in such a way that the position of the object as a function of time is give

kaheart [24]

Answer:

The work done by the force is 1435 Joule.

Explanation:

You have to apply the work-energy theorem, which associates the work and the mechanical energy

W of all non conservative forces = ΔEm = Emb - Ema

where Emb is the mechanical energy in point b and Ema is the mechanical energy in point a

Is also known that mechanical energy is the sum of potential energy and kinetic energy.

In this case, there is only kinetic energy because the potential energy is given by conservative forces like the weight but the weight is perpendicular to the displacement and because of that it doesn't produce work.

So, the work is given by:

W= Ekb - Eka, where Ek is the kinetic energy

By definition the kinetic energy is given by:

$Ek=\frac{1}{2}mV^{2}$ where m is the mass and V is the speed.

Replacing the definition of Ek in the equation of work:

$W=\frac{1}{2}mVb^{2} - \frac{1}{2}mVa^{2}$

So, you have to calculate the speed in point a and in point b

You can calculate the velocity of the object as a function of time derivating the equation of the position:

$V(t) = \frac{dX(t)}{dt} = \frac{d(3.0t-4.0t^{2}+1.0t^{3}) }{dt}$

$V(t)=3.0-8.0t+3.0t^{2}$

Replacing t=0 s to obtain the speed in the initial point (point a)

Va=3.0-8(0)+3.0(0)(0)

Va=3.0 m/s

Replacing t=5.0 to obtaing the speed in final point (point b)

Vb= 3-8(5)+3(5)(5) = 38 m/s

Therefore the work is:

$W = \frac{1}{2}(2.0)(38)^{2} - \frac{1}{2}(2.0)(3^{2}) =1444 - 9 = 1435 [J]$

<u>Where J is Joules, the unit for work.</u>

8 0

3 years ago

The noble gases have eight valence electrons and as a result are

AURORKA [14]

The noble gases have eight valence electrons and as a result are stable.

If an atom consists of 8 valence electrons, they have a full octet, and do not need to bond, which makes them "happy".

4 0

4 years ago

A long bar slides on two contact points and is in motion with velocity ν. A steady, uniform, magnetic field B is present. The in

fomenos

Answer:

The induced current in the resistor is I = BLv/R

Explanation:

The induced emf ε in the long bar of length, L in a magnetic field of strength, B moving with a velocity, v is given by

ε = BLv.

Now, the current I in the resistor is given by

I = ε/R where ε = induced emf in circuit and R = resistance of resistor.

So, the current I = ε/R.

substituting the value of ε the induced emf, we have

I = ε/R

I = BLv/R

So, the induced current through the resistor is given by I = BLv/R

5 0

3 years ago