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andre [41]
3 years ago
14

Using the equation MgCl2 -> Mg + Cl2, if 5.00 grams of MgCl2 is given, how many grams of Mg is produced?

Chemistry
1 answer:
motikmotik3 years ago
4 0

Answer:

MgCl2-> Mg+Cl

mass 5.00g Mass=1.263g

RFM Mg=24+35.5 ×2= 95 RFM= 24

moles= 5.00÷ 95= 0.0526 Moles=0.0526

Explanation:

mas of Mg= 1.263 grams

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Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the numbe
IceJOKER [234]

The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

<h3>Is BF3 molecule stable or not?</h3>

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

Learn more about molecule here: brainly.com/question/26044300

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5 0
1 year ago
Which part of an object's rate of change best defines acceleration?
Marat540 [252]

Answer:

Velocity

Explanation:

The change of velocity rate it's the definition of acceleration.

While increasing or decreasing velocity, it means that an acceleration it's happening.

Using some math:

a=\frac{dv}{dt}

This can be read as "the acceleration it's equal to te variation of velocity with respect to time"

8 0
3 years ago
Ethyl acetate can be prepared by an SN2 reaction. Draw the alkylbromide and nucleophile used in the reaction. Remember to includ
bulgar [2K]

Answer:

Few important points related to S_N2 reaction:

1. S_N2 is a one-step reaction that follows second order kinetics.

2. In S_N2 reaction, a transition state is formed in situ.

3. Strong nucleophiles like OH^- \ or\  CN^- are used in case of bi-molecular nucleophilic substitution reaction.

Ethyl acetate can be prepared by a second-order nucleophilic substitution reaction between acetic acid and ethyl bromide.  

The reaction between acetic acid and ethyl bromide is drawn below:

8 0
3 years ago
Read 2 more answers
ook at sample problem 18.12 in the 8th ed Silberberg book. Write a balanced chemical equation (salt hydrolysis). So acetate ion
vfiekz [6]

Answer:

Here's what I get  

Explanation:

1. Write the chemical equation

CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻; Kₐ = 2 × 10⁻⁵

Let's rewrite the equation as

A⁻ + H₂O ⇌ HA + OH⁻

2. Calculate Kb

K_{\text{b}} = \dfrac{K_{\text{w}}}{K_{\text{a}}} = \dfrac{1.00 \times 10^{-14}}{2 \times 10^{-5}} = 5 \times 10^{-10}

3. Set up an ICE table

                      A⁻ + H₂O ⇌ HA + OH⁻

I/mol·L⁻¹:      0.35                 0       0

C/mol·L⁻¹:       -x                  +x      +x

E/mol·L⁻¹:    0.35-x               x        x

4. Solve for x

\dfrac{\text{[HA ][OH$^{-}$]}}{\text{[A$^{-}$]}} = \dfrac{x^{2}}{0.35-x} = 5 \times 10^{-10}

Check for negligibility,

\dfrac{\text{[HA]}}{K_{\text{b}}} = \dfrac{0.35}{5 \times 10^{-10}} = 7 \times 10^{8}> 400\\\\\therefore x \ll 0.35\\\\\dfrac{x^{2}}{0.35} = 5 \times 10^{-10}\\\\x^{2} = 0.35 \times 5 \times 10^{-10} = 1.8\times 10^{-10}\\\\x = \sqrt{1.8\times 10^{-10}} = \mathbf{1 \times 10^{-5}}

5. Calculate the pOH

[OH⁻] = 1 × 10⁻⁵ mol·L⁻¹

pOH = -log[OH⁻] = -log(1 × 10⁻⁵) = 4.88

6. Calculate the pH.

pH + pOH = 14.00

pH + 4.88 = 14.00

pH = 9.12

Note: The answer differs from that given by Silberberg because you used only one significant figure for the Kₐ of acetic acid.

3 0
3 years ago
Altering the pressure of a system can affect the rate of a chemical reaction. true false
irga5000 [103]
The answer is false.
3 0
3 years ago
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