<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.
<u>Explanation:</u>
All radioactive decay processes undergoes first order reaction.
To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:
![k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%20%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken = 1.52 hrs
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= Initial concentration of reactant = 100 g
[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g
Putting values in above equation, we get:
To calculate the half life period of first order reaction, we use the equation:
where,
= half life period of first order reaction = ?
k = rate constant = 
Putting values in above equation, we get:
Hence, the half life of the sample of silver-112 is 3.303 hours.
Answer is: n (number of fluorine atoms) is 6, formula of the compound is XeF₆.
m(F) = 0.8682 g; mass of fluorine.
n(F) = m(F) ÷ M(F).
n(F) = 0.8682 g ÷ 19 g/mol.
n(F) = 0.0457 mol; amount of substance.
m(Xe) = 1.00 g.
n(Xe) = 1.00 g ÷ 131.293 g/mol.
n(Xe) = 0.00761 mol.
n(Xe) : n(F) = 0.00761 mol : 0.0457 mol.
n(Xe) : n(F) = 1 mol : 6 mol.
Answer:
Explanation:
When carbon dioxide dissolves and reacts with water, the water and the gaseous 
reacts to form a dilute mixture solution of 
(carbonic acid ).
The reaction is 
This is a forward reaction. And the symbol 
shows that the reaction can be reversible. It means that the reaction can be carried in forward direction as well as in the backward direction.
The reaction attains chemical equilibrium until the reactants and the products no longer changes with time.
The carbonic acid can also dissociates into carbon dioxide and water in the backward direction.
Answer:
1.1 × 10² g
Explanation:
First, we will convert 1.0 L to cubic centimeters.
1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³
The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:
1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g
1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:
1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g
Answer:
2
Explanation:
The balanced chemical equation for this reaction is:
2Na + K2S → 2K + Na2S
Meaning the coefficient for potassium (K) is 2.
