Question

You have two charges; Q1 and Q2, and you move Q1 such that the potential experienced by Q2 due to Q1 increases.

Answer 1

Given that,

First charge = Q₁

Second charge = Q₂

The potential experienced by Q2 due to Q1 increases

We know that,

The electrostatic force between two charges is defined as

$F=\dfrac{kQ_{1}Q_{2}}{r^2}$

Where,

k = electrostatic constant

$Q_{1}$= first charge

$Q_{2}$= second charge

r = distance

According to given data,

The potential experienced by Q₂ due to Q₁ increases.

We know that,

The potential is defined from coulomb's law

$V=\dfrac{Q_{1}}{4\pi\epsilon_{0}r}$

$V\propto\dfrac{1}{r}$

If r decrease then V will be increases.

If V decrease then r will be increases.

Since, V is increases then r will decreases that is moving Q₁ closer  to Q₂.

Hence, Moving Q₁ closer to Q₂.

(c) is correct option.