What would happen when two or more capacitors are connected in parallel across a potential difference?
1 answer:
Answer:
The Current Iₜ = I₁ + I₂ + I₃
Charge Qₜ = Q₁ + Q₂ + Q₃
Potential difference Vₜ = V₁ = V₂ = V₃
The total capacitance Cₜ = C₁ + C₂ + C₃
Explanation:
According to the attached image;
For parallel arrangements of capacitors, the current flowing through each of the capacitors sums up to the total current flowing through the circuit;
Iₜ = I₁ + I₂ + I₃
Also the charge storage by each capacitor sums up to give the total charge stored;
Qₜ = Q₁ + Q₂ + Q₃
The potential difference across each of the capacitors are the same and equal to the total voltage across the circuit;
Vₜ = V₁ = V₂ = V₃
The total capacitance equals the sum of the capacitances of each of the capacitors;
Cₜ = C₁ + C₂ + C₃
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Answer:
The near point of an eye with power of +2 dopters, u' = - 50 cm
Given:
Power of a contact lens, P = +2.0 diopters
Solution:
To calculate the near point, we need to find the focal length of the lens which is given by:
Power, P =
where
f = focal length
Thus
f =
f = = + 0.5 m
The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.
Now, by using lens maker formula:
where
u = object distance = 25 cm = 0.25 m = near point of a normal eye
u' = image distance
Now,
Solving the above eqn, we get:
u' = - 0.5 m = - 50 cm