What would happen when two or more capacitors are connected in parallel across a potential difference?
1 answer:
Answer:
The Current Iₜ = I₁ + I₂ + I₃
Charge Qₜ = Q₁ + Q₂ + Q₃
Potential difference Vₜ = V₁ = V₂ = V₃
The total capacitance Cₜ = C₁ + C₂ + C₃
Explanation:
According to the attached image;
For parallel arrangements of capacitors, the current flowing through each of the capacitors sums up to the total current flowing through the circuit;
Iₜ = I₁ + I₂ + I₃
Also the charge storage by each capacitor sums up to give the total charge stored;
Qₜ = Q₁ + Q₂ + Q₃
The potential difference across each of the capacitors are the same and equal to the total voltage across the circuit;
Vₜ = V₁ = V₂ = V₃
The total capacitance equals the sum of the capacitances of each of the capacitors;
Cₜ = C₁ + C₂ + C₃
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Answer:
Explanation:
Given that,
Mass of the bowling ball, m = 5 kg
Radius of the ball, r = 11 cm = 0.11 m
Angular velocity with which the ball rolls,
To find,
The ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball.
Solution,
The translational kinetic energy of the ball is :
The rotational kinetic energy of the ball is :
Ratio of translational to the rotational kinetic energy as :
So, the ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball is 5:2