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3 years ago

Birds which are famous for performing a ritualized mating dance

2 answers:

6 0

Birds which famous for performing a ritualized mating dance are: The Grebes

Grebes most commonly live near a fresh water source.

They conducted this ritual because When two Grebes with opposite sex dances near each other, they will release some sort of pheromones that make them attracted to one another.

AVprozaik [17]3 years ago

6 0

Birds which famous for performing a ritualized mating dance are:

The Grebes

Grebes most commonly live near a fresh water source.

They conducted this ritual because When two Grebes with opposite sex dances near each other, they will release some sort of pheromones that make them attracted to one another.

Explanation:

Hedge Sparrow Albatross Peacock Blue Manakin Grebe are also included.

Albatrosses are primitive birds that start their ritualized mating dance with shared grooming and then drive into a mating dance where they pat their bills and open their mouths. The gooney birds are typically observed as falling into four genera, yet there is disagreement over the quantity of specie.

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A material you are testing conducts electricity but canot be pulled into wires

agasfer [191]

A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metalloid. Hope this helps!

4 0

3 years ago

Decision making worksheet answer key

mario62 [17]

Answer:

do your mom hard to get out of the house you doing today no classes are you doing today no classes are you doing today no classes are not sleeping in my bed you have any best to get the meaning do you want for it is my friend I will be there at 12 I have send me a even if we don't ask everyone e for it was a screenshot I am excited everything except you eat your eyes everything except everything else ever even know if everyone e and 10 even though it was kiss emoji everything else ever eyebrows yet I eat early to get enough everything except everything is your class finish up early enough even know what is going on with out hajab I have send it out to edit a video on e a video on each e

Explanation:

7ün go up to the meaning of the name to the class finish it was in the picture of the meaning is F C B you send me your pic of clans go for a walk and 10 even though I am not say that you wake me up

7 0

2 years ago

A generator with �# ' = 300 V and Zg = 50 Ω is connected to a load ZL = 75 Ω through a 50-Ω lossless line of length l = 0.15λ. (

ki77a [65]

Answer:

a. Zin = 41.25 - j 16.35 Ω

b. V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

c. Pin = 216 w

d. PL = Pin = 216 w

e. Pg = 478.4 w , Pzg = 262.4 w

Explanation:

Zin = Zo * [ ZL + j Zo Tan (βl) ] / [ Zo + j ZL Tan (βl) ]

βl = 2π / λ * 0.15 λ = 54 °

Zin = 50 * [ 75 + j 50 Tan (54) ] / [ 50 + j 75 Tan (54) ]

Zin = 41.25 - j 16.35 Ω

I₁ = Vg / Zg + Zin ⇒ I₁ = 300 / 41.25 - j 16.35 = 3.24 e ¹⁰ ¹⁶

V₁ = I₁ * Zin = 3.24 e ¹⁰ ¹⁶ * ( 41.25 - j 16.35)

V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

Pin = ¹/₂ * Re * [V₁ * I₁]

Pin = ¹/₂ * 143.6 ⁻¹¹ ⁴⁶ * 3.24 e ⁻ ¹⁰ ¹⁶ = 143.6 * 3.24 / 2 * cos (21.62)

Pin = 216 w

The power PL and Pin are the same as the line is lossless input to the line ends up in the load so

PL = Pin

PL = 216 w

Pg Generator

Pg = ¹/₂ * Re * [ V₁ * I₁ ] = 486 * cos (10.16)

Pg = 478.4 w

Pzg dissipated

Pzg = ¹/₂ * I² * Zg = ¹/₂ * 3.24² * 50

Pzg = 262.4 w

4 0

3 years ago

In regards to the respiratory system; all of the following are true except

Iteru [2.4K]

Could you please provide the options? :)

7 0

3 years ago

A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high te

Nataly [62]

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

$\Delta L=\alpha L_{0}\Delta T$

Where:

L(0) is the initial length
ΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))
ΔL is the final length minus the initial length (L(f)-L(0))
α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)

So, we have:

$L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})$

$L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})$

$L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)$

$L_{f}=0.117\: m$

Therefore, the length at the final temperature is 11.7 cm.

I hope it helps you!

7 0

3 years ago