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ivolga24 [154]
3 years ago
6

PLZ HELP QUICK THIS IS URGENT

Mathematics
2 answers:
Nitella [24]3 years ago
7 0

Answer:

question 2

1/x^15

Step-by-step explanation:

irakobra [83]3 years ago
4 0

Answer:

Question 2: The lowest answer Choice.

Question 3: False

Question 4: The 1st Choice.

Question 5: 343/36

Step-by-step explanation:

Question 2:

The lowest Answer choice.

Question 3: 125 + 1/5 3

125+ 1/125 = 1

15626 = 1

15626 = 125 | We are going to check the Equality.

Equality = False.

Question 4: The 1st choice.

Question 5: 1/6 2 x 7 3

1/36 x 7 3

7 3/36

Solution :343/36

Branliest is Appreciated.

Hope this helped.

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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Matt started doing extra chores around the house and his allowance changed from $30 per week to $40 per week. What is the percen
slega [8]

Answer:

33.3%

Step-by-step explanation:

Let's say the percent change is x%. Then the equation is:

30 + x% * 30 = 40

Subtract 30 from both sides:

x% * 30 = 10

Divide by 30:

x% = 10/30 = 1/3

Remember that % simply means "out of 100", so:

x/100 = 1/3

Multiply both sides by 100:

x = (1/3) * 100 = 33.3%

3 0
3 years ago
Read 2 more answers
Simplify (1-√3)(⅓+√3) leaving your answer in the form p+q√3​
Mars2501 [29]

Answer:

\frac{-8 +2\sqrt{3} }{3}

Step-by-step explanation:

When working with surds we need to take note of the roots present there.

To expand this equation we can do it the following way noting that √3 X √3 = 3

<em></em>

<em>Expanding (1-√3)(⅓+√3)</em>

1 X 1/3 = 1/3

1 X √3 = √3

-√3 X 1/3 =-√3/3

√3 X √3 = 3

hence, expanding the equation, we have

1/3 + √3 -√3/3 + 3

We can simply group the like terms and add them up.

[1/3 +3] +[√3-√3/3]

10/3 + \frac{2\sqrt{3} }{3}

= \frac{-8 +2\sqrt{3} }{3}

8 0
3 years ago
The shadows of two vertical poles were measured at the same time to be 6m and 15m long. If the first pole is 8cm long, find the
son4ous [18]

Answer:

20 cm

Step-by-step explanation:

Shadow of vertical poles : 6m ; 15m

Length of poles : 8cm ; h

8cm long pole = shadow length, 6m

h cm long pole = shadow length, 15 m

Using cross multiplication :

8cm * 15 m = h cm * 6m

120 = 6h

h = 120 / 6

h = 20 cm

Height of second pole = 20cm

8 0
3 years ago
A) An empty bulldozer weighed 5 8 ⁄10 tons. If it scooped up 7 1 ⁄10 tons of dirt, what would be the combined weight of the bull
irakobra [83]

Answer: 12 9/10 and 10 7/8

Step-by-step explanation:

5 8/10 plus 7 1/10 equals 12 9/10

8 5/8 plus 2 2/8 equals 10 7/8

6 0
3 years ago
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