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WARRIOR [948]
3 years ago
10

1. The students were given the task of finding the density of a brownie. Johnny decided to eat ½ of his brownie before conductin

g his experiment. How would Johnny’s results compare with the rest of the class?
Chemistry
2 answers:
mario62 [17]3 years ago
8 0
Jonnys answer would be the same as his classmates because density does not depend upon the amount or size of a substance but on the composition of the substancw
andrew-mc [135]3 years ago
6 0

Answer:

Johnny's result will be identical compared with rest of class

Explanation:

  • Density is the ratio of mass to volume
  • If mass increases/decreases then volume also increases/decreases proportionally. Hence density remains constant
  • Johnny ate half of it's brownie. So mass of brownie becomes half of it's original mass. Volume of brownie also becomes half of it's original mass
  • Density of brownie = \frac{(mass)_{brownie}}{(volume)_{brownie}}=\frac{\frac{(mass)_{brownie}}{2}}{\frac{(volume)_{brownie}}{2}}
  • So Johnny's result will be identical compared with rest of class.
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When the temperature of a substance _____, the motion of the atoms that make up that substance _____.
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Increase in temperature makes the atoms speed up, and decrease in temperature makes the atoms move slower.
7 0
3 years ago
Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N 2 ( g ) + 3 H 2 ( g )
Kisachek [45]

Answer:

After complete reaction, 0.280 moles of ammonia are produced

Explanation:

Step 1: Data given

Number of moles N2 = 0.140 moles

Number of moles H2 = 0.434 moles

Step 2: The balanced equation

N2(g) + 3H2 (g) ⟶ 2NH3 (g)

Step 3: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.140 moles).

H2 is in excess. There will react 3*0.140 = 0.420 moles

There will remain 0.434 - 0.420 = 0.014 moles

Step 4: Calculate moles NH3

For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3

After complete reaction, 0.280 moles of ammonia are produced

5 0
3 years ago
Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2
Nutka1998 [239]

Answer:

b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.

There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.

I hope it helps!

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What are the parts of a nucleotide?
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B-sugar + phosphate + nitrogen base
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