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WARRIOR [948]
3 years ago
10

1. The students were given the task of finding the density of a brownie. Johnny decided to eat ½ of his brownie before conductin

g his experiment. How would Johnny’s results compare with the rest of the class?
Chemistry
2 answers:
mario62 [17]3 years ago
8 0
Jonnys answer would be the same as his classmates because density does not depend upon the amount or size of a substance but on the composition of the substancw
andrew-mc [135]3 years ago
6 0

Answer:

Johnny's result will be identical compared with rest of class

Explanation:

  • Density is the ratio of mass to volume
  • If mass increases/decreases then volume also increases/decreases proportionally. Hence density remains constant
  • Johnny ate half of it's brownie. So mass of brownie becomes half of it's original mass. Volume of brownie also becomes half of it's original mass
  • Density of brownie = \frac{(mass)_{brownie}}{(volume)_{brownie}}=\frac{\frac{(mass)_{brownie}}{2}}{\frac{(volume)_{brownie}}{2}}
  • So Johnny's result will be identical compared with rest of class.
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A student writes the following explanation of how certain molecules are formed.A process is used to chemically link smaller unit
tensa zangetsu [6.8K]

Answer:

polymerization

Explanation:

Student is explaining the process of formation of a polymer and the process is called polymerization.

Polymer is made up of joining repeating units. The repeating units are called monomers.  

Properties of the polymer is determined by the structure of monomer molecule.

For example, consider a well-known polymer Teflon.is made by the polymerization of tetrafluoroethane.  

Thus, the student is explaining polymerization.

8 0
3 years ago
What is the mass of 2.5 mol of ca, which has a molar mass of g/mol
swat32
Atomic mass Ca = 40 a.m.u

1 mole Ca ----------- 40 g
2.5 mols Ca -------- ( mass Ca )

Mass Ca = 2.5 x 40 / 1

Mass Ca = 100 / 1

= 100 g of Ca

hope this helps!
3 0
3 years ago
Can someone help me please I’m giving the brainliest
Len [333]
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3 0
3 years ago
How many moles of gas occupy 98L at a pressure of 2.8atm and a temperature of 292k? and what law would you use?
algol13
Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,
PV = nRT

Where, P is Pressure of the gas (Pa), V is volume of the gas (m³), n is the number of moles of gas (mol), R is the Universal gas constant (8.314 J mol⁻¹ K⁻¹) and T is the temperature in Kelvin (K)

The given data for the gas is,
P = 2.8 atm = 283710 Pa
V = 98 L = 98 x 10⁻³ m³
T = 292 K
R = 8.314 J mol⁻¹ K⁻¹
n = ?

By applying the formula,
283710 Pa x 98 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 292 K
                                       n = 11.45 mol

Hence,moles of gas is 11.45 mol.
8 0
3 years ago
Please help, I really don’t understand this!!!
kap26 [50]

<u>Analysing the Question:</u>

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>

<u>Moles of Glucose used in the reaction:</u>

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

<u>Mass of Oxygen required:</u>

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen  = 32 / 30

Mass of Oxygen = 1.06 grams

5 0
3 years ago
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