Because the resulting hybridized orbitals are more stable
Explanation:
N2O4(g) <----------> 2NO2(g)
Before proceeding,
A chemical equilibrium can be defined as a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.
Statement 1.
This statement is false. Equilibrium is not about equal concentrations but rather zero change in concentration of the reactants and products.
Statement 2.
This statement is True in chemical equilibrium; the forward and reverse reactions occur at equal rates.
Statement 3.
This statement is False. The rate constant for the forward reaction is not equal to the rate constant of the reverse reaction.
Statement 4.
The concentration of NO2 divided by the concentration of N2O4 is NOT equal to a constant. To obtain a constant value irregardless of the concentrations, the concentration of NO2 must be squared. This comes from the stoichiometry of the reaction
Kc= [NO2]2 / [N2O4]
This statement is false.
Answer:
it’s mass was greater than when it started
Explanation:
When a metal is coated with another metal, the plating metal deposits on the plated metal. Usually, the plating metal functions as the anode while the plated metal functions on the cathode. The anode metal is oxidized and reduced at the cathode and become deposited on the cathode material. This increases the mass of the cathode. Hence the mass of the silver/gold product is greater than the mass of silver at the beginning of the electroplating process.
Answer:
x=34
y=20
Explanation:
let the first number be 'x'
let the second number be 'y'
Equation 1:-
x + y = 54
Equation 2:-
x = y + 14 (Since one exceeds the other by 14)
Substituting Equation 2 in Equation 1:-
(y + 14) + y = 54
=> y + 14 + y = 54
=> 2y + 14 = 54
=> 2y = 54 - 14
=> 2y = 40
=> y = 40/2
=> y = 20
Now in Equation 1:-
x + y = 54
Substituting y=20,
x + 20 = 54
x = 54 - 20
x = 34
Answer: (D) 0.025 mol 
Explanation:
The given balanced equation is :
According to stoichiometry :
4 moles of ammonia 
reacts with = 5 moles of oxygen 
Thus 0.30 moles of ammonia reacts with = 
moles of oxygen
Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.
moles of oxygen left = 0.40 - 0.375 = 0.025
Thus 0.025 mol excess reagent remains.
