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UkoKoshka [18]
3 years ago
14

Question is in the image

Mathematics
2 answers:
kati45 [8]3 years ago
6 0

Answer:

y=(-2/3)x^2

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
4 0
<h3>Answer:  g(x) = (-2/3)x^2</h3>

=====================================================

Explanation:

The blue parent function has a positive coefficient of 1. The purple g(x) function is a reflection of f(x) over the x axis, so everything is now negative. The coefficient must be negative as well.

But the answer is simply not g(x) = -x^2 because plugging x = 3 does not lead to y = -6 as the point (3,-6) shows.

Let's say the coefficient is k for now. So we have y = kx^2

Plug in x = 3 and y = -6. Solve for k

y = kx^2

-6 = k(3)^2

-6 = k*9

9k = -6

k = -6/9

k = -2/3

So we update y = kx^2 into y = (-2/3)x^2

Meaning that g(x) = (-2/3)x^2 is the equation of the purple curve.

Plug x = 3 into g(x) to find that

g(x) = (-2/3)x^2

g(3) = (-2/3)(3)^2

g(3) = (-2/3)(9)

g(3) = -6

which is the output we want, so this confirms we have the correct coefficient.

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3 years ago
Find the value of a and b if root3-1/root3+1+ root3+1/root3-1=a+root3 b​
Digiron [165]

Answer:

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Step-by-step explanation:

Given : \dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b

To find, The value of a and b

Solution,

Solving LHS of the given equation,

\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b

Since,

(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2

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4+0=a+\sqrt 3 b

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4 0
3 years ago
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alina1380 [7]

Answer:

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33.60-6.72= 26.88

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3 years ago
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