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fiasKO [112]
3 years ago
12

The densities of several materials are given in SI units. Convert these to densities in U.S. customary units (slug/ft3), and als

o compute the specific weights of these materials in U.S. customary units (lb/ft3).The density of ceramic (alumina Al2O3), rho = 3.9 Mg/cm3.

Engineering
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

a) Density of Lead = 22.0029 slug/ft3

b) Density of Ceramic Alumina = 7567163.99 slug/ft3

c) Density of polyethylene = 1.8626slug/ft3

d) Density of Balsa wood = 0.388slug/ft3

Explanation:

The question is incomplete as other information's are missing, here is the complete question ;

The densities of several materials are given in SI units . Convert these to densities in U.S . Customary units (slug/ft3), and also compute the specific weights of these materials in U.S . Customary units (lb/ft3). (a) Lead (pure), p = 11.34g/cm3. (b) Ceramic (alumina Al2O3), p = 3.90 Mg/cm3. (c) Polyethylene (high density), p = 960 kg/m3. (d) Balsa wood, p = 0.2 Mg/m3.

The specific weight is the weight per unit volume, i.e W = mg

but mass = density x volume

W = rho x v x g = (rho)vg

W/v = rho x g

where W/v = is the specific weight and g = is the acceleration due to gravity depending on the units, but in this case as told, g is in the US Customary units (lb/slug) which is 32.2 from conversion factor, and since we are told to calculate the specific weight of each in lb/ft3.

All you have to do is to multiply each density by the acceleration due to gravity and

repeat the same step for each of the materials.

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5 0
2 years ago
Given a matrix, clockwise-rotate elements in it. Please add code to problem3.cpp and the makefile. Use the code in p3 to test yo
rusak2 [61]

Answer:

/* C Program to rotate matrix by 90 degrees */

#include<stdio.h>

int main()

{

int matrix[100][100];

int m,n,i,j;

printf("Enter row and columns of matrix: ");

scanf("%d%d",&m,&n);

 

/* Enter m*n array elements */

printf("Enter matrix elements: \n");

for(i=0;i<m;i++)

{

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 {

  scanf("%d",&matrix[i][j]);

 }

}

 

/* matrix after the 90 degrees rotation */

printf("Matrix after 90 degrees roration \n");

for(i=0;i<n;i++)

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  printf("%d  ",matrix[j][i]);

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 printf("\n");

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return 0;

 

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5 0
3 years ago
A pipeline (NPS = 14 in; schedule = 80) has a length of 200 m. Water (15℃) is flowing at 0.16 m3/s. What is the pipe head loss f
dangina [55]

Answer:

Head loss is 1.64

Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

We know, head\ loss  = \frac{f L V^2}{( 2 g D)}

where, f = Darcy friction factor

V = flow velocity

g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

V = \frac{Q}{A}

    = \frac{0.16}{\frac{\pi}{4} (0.318)^2} = 2.015 m/s

obtained Darcy friction factor  

calculate Reynold number (Re) ,

Re = \frac{\rho V D}{\mu}

where,\rho = density of water

\mu = Dynamic viscosity of water at 15 degree  C = 0.001 Ns/m2

so reynold number is

Re = \frac{1000\times 2.015\times 0.318}{0.001}

            = 6.4 x 10^5

For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = \frac{0.0126 (200)(2.015)^2}{( 2 \times 9.81 \times 0.318)}

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7 0
3 years ago
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VashaNatasha [74]

Answer: B

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Hope this helps!

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3 years ago
Read 2 more answers
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Explanation:

Okay soo-

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a = -5/12

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Good luck!

5 0
2 years ago
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