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fiasKO [112]
3 years ago
12

The densities of several materials are given in SI units. Convert these to densities in U.S. customary units (slug/ft3), and als

o compute the specific weights of these materials in U.S. customary units (lb/ft3).The density of ceramic (alumina Al2O3), rho = 3.9 Mg/cm3.

Engineering
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

a) Density of Lead = 22.0029 slug/ft3

b) Density of Ceramic Alumina = 7567163.99 slug/ft3

c) Density of polyethylene = 1.8626slug/ft3

d) Density of Balsa wood = 0.388slug/ft3

Explanation:

The question is incomplete as other information's are missing, here is the complete question ;

The densities of several materials are given in SI units . Convert these to densities in U.S . Customary units (slug/ft3), and also compute the specific weights of these materials in U.S . Customary units (lb/ft3). (a) Lead (pure), p = 11.34g/cm3. (b) Ceramic (alumina Al2O3), p = 3.90 Mg/cm3. (c) Polyethylene (high density), p = 960 kg/m3. (d) Balsa wood, p = 0.2 Mg/m3.

The specific weight is the weight per unit volume, i.e W = mg

but mass = density x volume

W = rho x v x g = (rho)vg

W/v = rho x g

where W/v = is the specific weight and g = is the acceleration due to gravity depending on the units, but in this case as told, g is in the US Customary units (lb/slug) which is 32.2 from conversion factor, and since we are told to calculate the specific weight of each in lb/ft3.

All you have to do is to multiply each density by the acceleration due to gravity and

repeat the same step for each of the materials.

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A sample of sand weighs 490 g in stock and 475 in Oven Dry (OD) condition, respectively. If absorption capability of the sand is
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The weight of the specimen in SSD condition is 373.3 cc

<u>Explanation</u>:

a) Apparent specific gravity = \frac{A}{A-C}

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B = saturated surface test sample in air = 1048.9 g

C = apparent mass of saturated test sample in water = 975.6 g

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3 years ago
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drek231 [11]

Answer:

Hardness is understood as the property of materials in general to resist the penetration of an indenter under load, so that the hardness represents the resistance of the material to the plastic deformation located on its surface.

Explanation:

Hardness of a material is understood as the resistance that the material opposes to its permanent surface plastic deformation by scratching or penetration. It is always true that the hardness of a material is inversely proportional to the footprint that remains on its surface when a force is applied.

In this sense, the hardness of a material can also be defined as that property of the surface layer of the material to resist any elastic deformation, plastic or destruction due to the action of local contact forces caused by another body (called indenter or penetrator), harder, of certain shape and dimensions, which does not suffer residual deformations during contact.

That is, hardness is understood as the property of materials in general to resist the penetration of an indenter under load, so that the hardness represents the resistance of the material to the plastic deformation located on its surface.

The following conclusions can be drawn from the previous definition of hardness:  

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  2) the methods of hardness by indentation presuppose the presence of contact efforts, and therefore, the hardness can be quantified within a scale;

  3) In any case, the indenter or penetrator must not undergo residual deformations during the test of hardness measurement of the body being tested.

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