Answer:
Hello your question has some missing information below are the missing information
The refrigerant enters the compressor as saturated vapor at 140kPa Determine The coefficient of performance of this heat pump
answer : 2.49
Explanation:
For vapor-compression refrigeration cycle
P1 = P4 ; P1 = 140 kPa
P2( pressure at inlet ) = P3 ( pressure at outlet ) ; P2 = 800 kPa
<u>From pressure table of R 134a refrigerant</u>
h1 ( enthalpy of saturated vapor at 140kPa ) = 239.16 kJ/kg
h2 ( enthalpy of saturated liquid at P2 = 800 kPa and t = 60°C )
= 296.8kJ/kg
h3 ( enthalpy of saturated liquid at P3 = 800 kPa ) = 95.47 kJ/kg
also h4 = 95.47 kJ/kg
To determine the coefficient of performance
Cop = ( h1 - h4 ) / ( h2 - h1 )
∴ Cop = 2.49
Answer:
The result in terms of the local Reynolds number ⇒ Re = [μ_∞ · x] / v
Explanation:
See below my full workings so you can compare the results with those obtained from the exact solution.
Answer:
management engineer
Explanation:
A Management Engineer is someone with a commercial engineering understanding and marketing techniques.
The role of a management engineer covers overseeing the activities of all the engineering departments in an engineering firm particularly in the area of product development, implementation, and production.
This is to ensure the products meet and satisfy the business methods and techniques specifically in the area of cost efficiency and quality product.
Under Management Engineering there are subdivisions of Manufacturing and Industrial Engineer, which both fit the role of Malcolm.
Hence, in this case, Malcolm work as a Management Engineer
Answer:
The shaft work generated per kilogram is 
Explanation:
Given:
Temperature 
K
Initial Pressure 
MPa
Final pressure 
MPa
From the table superheated,
and 
Work done by shaft is,
But here efficiency is 0.56,
So work generated per kg is,
Work = 
Work = 
Therefore, the shaft work generated per kilogram is
Answer:
Please see the attached file for the complete answer.
Explanation:
