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xxTIMURxx [149]
2 years ago
14

Explain why the following scenario fails to meet the criteria for proper reverse engineering.

Engineering
1 answer:
avanturin [10]2 years ago
5 0

Answer:

he must document or remember the order he took it apart so he put it back together

Explanation:

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Blank is common during exercise.
dsp73

Answer:

Sweat

Explanation:

As you exercise you respire and warm up due to energy. In turn, two things happen, blood vessels vasodilate (irrelevant to you) and sweat glands sweat more. this sweat then evaporates and cools down the body.

7 0
2 years ago
BAGAIMANA CARA MENINGKATKAN PRODUKTIVITAS ? APA SAJA VARIABEL
morpeh [17]

Answer:

;-;

Explanation:

am i dyslexic or is this another language

5 0
3 years ago
Read 2 more answers
A water tank is completely filled with liquid waterat 20°C.The tank material is such that it can withstand tensioncaused by a vo
Xelga [282]

Answer:

Highest temperature rise allowable = ΔT = 21.22°C

Highest allowable temperature = ΔT + 20 = 41.22°C

Explanation:

From literature, the coefficient of volume expansion of water between 20°C and 50°C = β = (0.377 × 10⁻³) K⁻¹

Volume expansivity is given by

ΔV = V β ΔT

ΔV = Change in volume

V = initial volume

β = Coefficient of volume expansion = (0.377 × 10⁻³) K⁻¹ = 0.000377 K⁻¹

ΔT = Change in temperature = ?

It is given in the question that maximum volume increase the tank can withstand is

(ΔV/V) × 100% = 0.8%

(ΔV/V) = 0.008

V β ΔT = ΔV

β ΔT = (ΔV/V)

β ΔT = 0.008

ΔT = (0.008/β)

ΔT = (0.008/0.000377)

ΔT = 21.22°C

Highest temperature rise allowable = ΔT = 21.22°C

Highest allowable temperature = ΔT + 20 = 41.22°C

Hope this Helps

5 0
4 years ago
What are the assumptions made for air standard cycle analysis?
diamong [38]
D i took this hope it helps
4 0
3 years ago
In the following code, determine the values of the symbols here and there. Write the object code in hexadecimal. (Do not predict
allsm [11]

Answer:

Answer explained below

Explanation:

The value of here is 9

The value of there is hexadecimal value of DECO here, d = 0x39 aaaa (aaaa is the memory address of here )

We have the object code :-

let's take there address is 0x0007

0x0005 BR there :- 0x120020

0x0007 here: .WORD 9

310003 there: DECO here,d - 0x390007

310005 STOP

.END

4 0
3 years ago
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