Answer: 9.9KJ
Explanation: Q = U + W + losses
Q is heat transfered to the water
U is the change in energy of the system
W is work done by the system = 2J
Losses = 80J
Heat into system is 10kJ = 10000KJ
Therefore
U = Q - W - losses
U = 10000 - 2 - 80 = 9990J
= 9.9kJ
Answer:
61257.6 kW per day
Explanation:
The rating of the refrigerator is given as : 709 w
This means the power consumption is 709 joules per second
The operating time is given as 10 hours.
Change hours to second as
1 hour = 3600 seconds
10 hours = 36000 seconds
Apply the rating as;
709 w = 1 s
? = 36000 seconds
perform cross product to get;
709 * 36000= 25524000 w
25524000 = 25524kW
For a day, 24 hours will be;
25524 kW = 10 hours
? =24 hours
={24*25524}/10 = 61257.6 kW per day
Answer:
Between 35°– 45°
Explanation:
In the vertical position, Point the flame in the direction of travel. Keep the flame tip at the correct height above the base metal. An angle of 35°–45° should be maintained between the torch tip and the base metal. This angle may be varied up or down to heat or cool the weld pool if it is too narrow or too wide
