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ololo11 [35]
4 years ago
8

A piece of copper wire is formed into a single circular loop of radius 18 cm. A magnetic field is oriented parallel to the norma

l to the loop, and it increases from 0 to 0.54 T in a time of 0.57 s. The wire has a resistance per unit length of 4.9 x 10-2 /m. What is the average electrical energy dissipated in the resistance of the wire
Physics
1 answer:
MA_775_DIABLO [31]4 years ago
3 0

Answer:

0.0956431731568 J

Explanation:

N = Number of turns = 1

r = Radius = 18 cm

A = Area = \pi r^2

\dfrac{dB}{dt}=\dfrac{0.54}{0.57}

Induced voltage is given by

V=NA\dfrac{dB}{dt}\\\Rightarrow V=1\times\pi 0.18^2\times \dfrac{0.54}{0.57}\\\Rightarrow V=0.096430359767\ V

Resistance is

R=2\pi rR/m\\\Rightarrow R=2\pi 0.18\times 4.9\times 10^{-2}\\\Rightarrow R=0.0554176944093\ \Omega

Power is given by

P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{0.096430359767^2}{0.0554176944093}\\\Rightarrow P=0.167795040626\ W

Energy

E=Pt\\\Rightarrow E=0.167795040626\times 0.57\\\Rightarrow E=0.0956431731568\ J

The average electrical energy dissipated is 0.0956431731568 J

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The critical angle of diamond is 24 degrees. What is its refractive index?
jolli1 [7]

Answer:

2.46

Explanation:

From the question given above, the following data were obtained:

Critical angle (C) = 24 °

Refractive index (n) =?

The refractive index of the diamond can be obtained by using the following formula as illustrated below:

Refractive index (n) = 1 / sine [critical angle (C)]

n = 1/sine C

n = 1 / sine 24 °

n = 1/0.4067

n = 2.46

Thus, the refractive index of the diamond is 2.46

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3 years ago
A projectile starts from rest and moves 4.8 m down a frictionless ramp inclined at 14◦ with the horizontal. The acceleration of
Sunny_sXe [5.5K]

Answer:166.32 m/s 2

Explanation:

6 0
4 years ago
Iron filings were mixed together with salt crystals. What unique property of iron would be BEST to separate the filings from the
Mashcka [7]
The melting point. So d is ur answer. The color and texture of both is the same. They sont have magnetism. So the only logical one is melting point.

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6 0
3 years ago
Read 2 more answers
A freight car of mass M contains a mass of sand m. At t = 0 a constant horizontal force F is applied in the direction of rolling
Veronika [31]

Answer:

Amount of linear movement

Explanation:

Our system is defined by the rate of change in mass that

leaves the car \Delta m_ {s} , this happens during a time interval

[t, t + \Delta t], in addition to freight car and sand at time t.

In this way we need to define the two states:

State 1,

consider t, m_ {c} (t) + \Delta m_ {s} and V.

State 2,

consider t + \Delta t, m_ {c} (t), V + V \Delta V

In this state is the mass of sand output, which

is composed of

\Delta m_{s}, V + \Delta V

In this way we define the Linear movement in x, like this:

p_ {x} (t) = (\Delta m_ {s} + m_ {c} (t)) v

p_ {x} (t+\Delta t) = (\Delta m_ {s} + m_ {c} (t)) (v + \Delta v)

m_ {c} (t) = m_ {c, 0} - bt = m_ {c} + m_ {s} -bt

In this way we proceed to obtain the Force

F =\lim_{\Delta t \rightarrow 0} \frac {p_x (t + \Delta t) -p_ {x} (t)} {\Delta t}

F = lim_{\Delta t \rightarrow 0} m_ {c} (t) \frac {\Delta v} {\Delta t} + lim_{\Delta t \rightarrow 0} m_ {s} (t) \frac {\Delta v} {\Delta T}

Since the mass of the second term becomes 0, the same term is eliminated, thus,

F = m_ {c} (t) \frac {dv} {dt}

\int\limit ^ {v (t)} _ {v = 0} dv = \int\limit^t_0 \frac{Fdt} {m_ {c} + m_ {s} -bt}

V (t) = - \frac {F} {b} ln (\frac {m_c + m_s-bt} {m_c + m_s})

3 0
4 years ago
The relationship between energy (E), power (P), and time (t) is
NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that E = 2000\,Cal and t = 1\,day, the power of body, measured in watts, is:

P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}

P = 96.898\,W

The avarage power of the body is 96.898 watts.

3 0
4 years ago
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