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astra-53 [7]
2 years ago
5

In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively

charged particle that moves from A to B along path 1 is W1.
How much work is done on this particle if it later goes from A to B along path 2? Express your answer in terms of W1.

W2=??​
Physics
1 answer:
Elanso [62]2 years ago
8 0

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

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Two objects are electrically charged. The net charge on one object is doubled. Therefore, the electric force _____.
creativ13 [48]
If net charge on one object is doubled, then electric force will also get double. It is because they are directly proportional to each other.

Hope this helps!
7 0
3 years ago
Read 2 more answers
3. A football is kicked with a speed of 35 m/s at an angle of 40°.
jarptica [38.1K]

a) 22.5 m/s

The initial vertical velocity is given by:

u_y = u sin \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_y = (35)(sin 40)=22.5 m/s

b) 26.8 m/s

The initial horizontal velocity is given by:

u_x = u cos \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_x = (35)(cos 40)=26.8 m/s

c) 2.30 s

The time it takes for the ball to reach the maximum heigth can be found by considering the vertical motion only. This is a uniformly accelerated motion (free-fall), so we can use the suvat equation

v_y = u_y + at

where

v_y is the vertical velocity at time t

u_y = 22.5 m/s

a=g=-9.8 m/s^2 is the acceleration of gravity (negative because it is downward)

At the maximum height, the vertical velocity becomes zero, v_y =0; substituting, we find the time t at which this happens:

0=u_y + gt\\t=-\frac{u_y}{g}=-\frac{22.5}{-9.8}=2.30 s

d) 25.8 m

The maximum height can also be found by considering the vertical motion only. We can use the following suvat equation:

s=u_y t + \frac{1}{2}gt^2

where

s is the vertical displacement at time t

u_y = 22.5 m/s

g=-9.8 m/s^2

Substituting t = 2.30 s, we find the displacement at maximum height, so the maximum height:

s=(22.5)(2.30)+\frac{1}{2}(-9.8)(2.30)^2=25.8 m

e) 123.3 m

In order to find how far does the ball lands, we have to consider the horizontal motion.

First of all, the time it takes for the ball to go back to the ground is twice the time needed for reaching the maximum height:

t=2(2.30 s)=4.60 s

Then, we consider the horizontal motion. There is no acceleration along this direction, so the horizontal velocity is constant:

v_x = 26.8 m/s

Therefore, the horizontal distance travelled during the whole motion is

d=v_x t = (26.8)(4.60)=123.3 m

So, the ball lands 123.3 m far from the initial point.

4 0
3 years ago
Which of the following materials could have been found in the giant cloud that formed the solar system?
iren2701 [21]
Liquid and solid water were not in the giant gas cloudr
6 0
3 years ago
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. A vertical electric field is set up in space to compensate for the gravitational force on a point charge. What is the required
Delicious77 [7]

(a) The required magnitude of the electric field when the point charge is an electron is 5.57 x 10⁻¹¹ N/C.

(b) The required magnitude of the electric field when the point charge is an proton is 1.02 x 10⁻⁷ N/C.

<h3>Magnitude of electric field </h3>

The magnitude of electric field is given by the following equation.

F = qE

But F = mg

mg = qE

E = mg/q

where;

  • E is the electric field
  • m is mass of the particle
  • g is acceleration due to gravity
  • q is charge of the particle
<h3>For an electron</h3>

E = (9.11 x 10⁻³¹ x 9.8)/(1.602 x 10⁻¹⁹)

E = 5.57 x 10⁻¹¹ N/C

<h3>For proton</h3>

E = (1.67 x 10⁻²⁷ x 9.8)/(1.602 x 10⁻¹⁹)

E = 1.02 x 10⁻⁷ N/C

Thus, the required vertical electric field is greater when the charge is proton.

Learn more about electric field here: brainly.com/question/14372859

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2 years ago
A(n) ________ is a specialized bursa that wraps around a tendon to reduce friction.
Kisachek [45]

Tendon Sheath - is a specialized bursa that wraps around a tendon to reduce friction.

<h3>What is Tendon Sheath ?</h3>

Tendon Sheath is a thin layer of tissue, surrounds each tendon in our body. The tendon sheath can also be called synovial lining or fibrous sheath. Tendon sheaths help to protect tendons from abrasive damage as they move.

Connection between Bursa and Tendon Sheath : Bursae are small fluid-filled sacs that can lie under a tendon, cushioning the tendon and protecting it from the injury. Bursae also provides an extra cushioning to adjacent structures that otherwise might rub against each other, which will cause wear and tear ( example, between a bone and a ligament ) .

So, lastly we can say that Tendon Sheath is the specialized bursa that wraps around a tendon to reduce friction.

To know more about Tendon Sheath please click here : brainly.com/question/17087116

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8 0
1 year ago
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