In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively
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I’m sorry if i took up a lot of space, hope this is a valid approximate answer
Answer:
The answer is "".
Explanation:
Its minimum velocity energy is provided whenever the satellite(charge 4 q) becomes 15 m far below the square center generated by the electrode (charge q).
It's ultimate energy capacity whenever the satellite is now in the middle of the electric squares:
Potential energy shifts:
Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.
This satellite is transmitted by it system at a height of 300 km and not in orbit, any other mechanism is required to bring the satellite into space.