Formula: molality, m = n solute / kg solvent
n solute = # of moles of solute = mass(g) / molar mass
Molar mass of Mg Br2 = 184.11 g/mol
m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg
Answer:
Mass = 4.44 g
Explanation:
Given data:
Number of moles of Ne = 0.220 mol
Mass in gram = ?
Solution:
Formula:
Number of moles = mass/ molar mass
Molar mass of Ne = 20.2 g/mol
by putting values,
0.220 mol = mass/ 20.2 g/mol
Mass = 0.220 mol × 20.2 g/mol
Mass = 4.44 g
Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions
We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M
The final concentration is 1.5 M
