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IceJOKER [234]
3 years ago
7

How many molecules of NH3 are produced from 4.72x10 negative 4 power g of H2?

Chemistry
1 answer:
Delvig [45]3 years ago
7 0
<span>9.40x10^19 molecules.
   The balanced equation for ammonia is:
 N2 + 3H2 ==> 2NH3
   So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
 Atomic weight nitrogen = 14.0067
  Atomic weight hydrogen = 1.00794

   Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
 Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol

   Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
   Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol

Now to convert from moles to molecules, just multiply by Avogadro's number: 1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
   Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
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3 0
3 years ago
Student took 1.52ml of a stock CuSO4 solution, with a given concentration of 3.26mg/ml. He then added water to the solution unti
Bumek [7]

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

<span>3.26 x 1.52 = 13.26 x M2</span>

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4 0
3 years ago
If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O
Luden [163]

Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of C_4H_{10} = 1.332 mol

Mass of O_2 = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:  

C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the balanced reaction we conclude that

As, 13 mole of O_2 react with 1 mole of C_4H_{10}

So, 6.504  moles of O_2 react with \frac{6.504}{13}=0.5003 moles of C_4H_{10}

From this we conclude that, C_4H_{10} is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

5 0
4 years ago
A fictional cubed-shaped bacterium, Bacterius cubis, occupies a volume of 2.0 femtoliters. This particular type of bacteria is k
umka2103 [35]

Answer:

There are  \mathbf{8.90172 \times 10^{-14}} moles of bactoX present in a 3.0 μL sample volume that contains 7.512×106 bacterial cells

Explanation:

Given that:

The number of molecules present in one bacterial cell is 7.140 \times 10^3 molecules

and the sample  contains 7.512 \times 10^6 molecules.

Number of moles = number of molecules /Avogadro's number

where;

Avogadro's number = 6.023 × 10²³

Number of moles = \dfrac{7.140 \times 10^3}{6.023 \times 10^{23}}

Number of moles = 1.185 \times 10^{-20} moles

So;  1.185 \times 10^{-20} moles  is present in one bacteria cell

Similarly;  the sample  contains 7.512 \times 10^6 molecules.

Therefore; the number of moles present in the bactoX is = 1.185 \times 10^{-20} \times 7.512 \times 10^6

= \mathbf{8.90172 \times 10^{-14}} moles

3 0
4 years ago
The red and yellow diamond in a NFPA sign represents what?
Snezhnost [94]

The red diamond tells how flammable the chemical compound is or how easily it catches fire.

The yellow diamond tells about reactivity how quickly the compound reacts with other materials.

3 0
3 years ago
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