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sergij07 [2.7K]
3 years ago
14

Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants t

o let his parents know that he is stuck down in the basement. He can either yell as loudly as he can, bang on the metal pipes, or bang on the concrete wall. Which should he do if he wants someone to hear him? Explain your answer, and explain why the other options would not be as effective.
Chemistry
2 answers:
solmaris [256]3 years ago
4 0

Answer:

he can bang metal pipes but i would rather say that he has to yell for help

Explanation:

why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out

hope this helped

Novay_Z [31]3 years ago
4 0

Answer:

Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants to let his parents know that he is stuck down in the basement. He can either yell as loudly as he can, bang on the metal pipes, or bang on the concrete wall. Which should he do if he wants someone to hear him? Explain your answer, and explain why the other options would not be as effective.

Explanation:

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What is the percent composition of NaHCO3?
zhuklara [117]

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

8 0
3 years ago
In a 1.0-liter container there are, at equilibrium, 0.10 mole h2, 0.20 mole n2, and 0.40 mole nh3. what is the value of kc for t
bogdanovich [222]
The reaction involved here would be written as:

2N2 + 3H2 = 2NH3

The equilibrium constant of a reaction is the ratio of the concentrations of the products and the reactants when in equilibrium. The expression for the equilibrium constant of this reaction would be as follows:

Kc = [NH3]^2 / [N2]^2[H2]^3
Kc = 0.40^2 / (0.20)^2 (0.10)^3 
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Answer:

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Explanation:

Correct on edge

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Answer:

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Explanation:

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