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zimovet [89]
3 years ago
10

How many moles of NaCl are present in 530 ml of a 1.52m NaCl solution

Chemistry
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

805.6 moles

Explanation:

Molarity = 1.52mL

Volume = 530mL

1.52 moles is present in 1mL,

1mL = 0.001L

1.52 moles = 0.001L

X moles = 0.53L

X = (1.52 × 0.53) / 0.001

X = 805.6moles

805.6moles is present in 530mL or 0.52L

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Consider the reaction of NO and CO to form N2 and CO2, according to the balanced equation: 2 NO (g) + 2 CO (g) → N2 (g) + 2 CO2
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The image is not given in the question, it is attached below:

<u>Answer:</u> The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

<u>Explanation:</u>

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide (CO_2) compound

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Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

We are given:

Given moles of NO = 6 moles

Given moles of CO = 4 moles

For the given chemical equation:

2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)

By stoichiometry of the reaction:

If 2 moles of CO reacts with 2 moles of NO

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Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

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