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boyakko [2]
3 years ago
5

Hydrofluoric acid is used to etch grooves in glass because it reacts with the silica (sio2(s)) in glass. the products of the rea

ctions are aqueous silicon tetrafluoride and water. what is the coefficient of silica in the balanced equation for the reaction? (balance the equation with the smallest possible whole number coefficients.)
Chemistry
2 answers:
kvv77 [185]3 years ago
6 0
Answer is: coefficient is one.
Chemical reaction: SiO₂ + 4HF → SiF₄ + 2H₂O.
Reaction is balanced when there are equal numbers of elements in both side of the chemical reaction.
HF - hydrofluoric acid, <span>highly corrosive, dissolves many materials.</span>
SiF₄ - silicon tetrafluoride.
Gnoma [55]3 years ago
5 0

Answer:

1

Explanation:

Chemical reaction: SiO₂ + 4HF → SiF₄ + 2H₂O.

In front of the silica there is no number which makes it an automatic 1.

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_____ chemical reactions need a certain amount of activation energy to get started.
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Answer:all

Explanation:

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Explain, in your own words, why different elements produce different colors of light when heated.
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A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40
Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = 40 hr/week\times 8 week = 320 hours

The concentration of xylene in the workplace =40 \mu g/m^3

The worker is inhaling air at a rate of 0.9 m^3/hr.

Amount xylene inhaled by worker in an hour :

= 40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr

Amount xylene inhaled by worker in 320 hours:

36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

\frac{24}{320}\times 11.520 mg=0.864 mg

Assuming 70 kg body mass, the chronic daily intake of xylene :

\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0
3 years ago
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cricket20 [7]

Answer:

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2H+  +  2Cl-  + Zn(s) --> H2(g) + Zn2+  + 2Cl-

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b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

8 0
2 years ago
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