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bogdanovich [222]
3 years ago
7

How many moles are in 458 grams of na2so4

Chemistry
1 answer:
shtirl [24]3 years ago
5 0

# moles = mass (g) / Mr (relative atomic mass)

# moles = 458 / ((23*2)+32+(16*4)

# moles= 458 /  142 = 3.2253521126760...

= 3.23 moles

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4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration
anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

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3 0
2 years ago
How to tell which element is oxidized in a reaction?
adoni [48]
If in a redox reaction oxidation state of elements decreases or looses electron(s), the element is said to be oxidized. Hope this helps you!
4 0
3 years ago
What is the mole fraction of a nonelectrolyte in an aqueous solution above which the vapor pressure of water is 745 mm Hg at 100
12345 [234]

The mole fraction of a gaseous compound is equal to the ratio of the vapor pressure of the compound to the total pressure of the vessel. In this case, teh vapor pressure of tehe non-electrolyte is 760 - 745 = 15 mmHg. hence the mole fraction is 15 mm Hg / 760 mmHg equal to 0.0197
3 0
3 years ago
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A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol
Marat540 [252]

Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

                               1 gallon = 3.78541 L

                               4. 50 gallon = 3.785 L x 4.50

So,                        

initial volume V1 =  17.03 L

final Volume V2 = ?

initial Temperature T1  = 80° F

convert Temperature to Kelvin

                              T1 = ( 80° F -32) / 1.8 +273

                               T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

                                  T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

                      V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

                      V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

V2 =  17.03 L x 373 K / 299.7 K

V2 =  21. 19 L

So the final volume of Methane gas = 21.19 L

Or for Volume in gallons

1 L = 0.26

21.19 x 0.264 = 5.6 gallons

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Forms when lava and magma cool (A)
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