All categories

3 years ago

The gure below shows partidos

Chemistry

1 answer:

Lubov Fominskaja [6]3 years ago

4 0

Answer:

Because the particles in solids are very close together making the particles tightly packed.

Explanation:

You might be interested in

A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re

Lilit [14]

Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

mass of reactant that release 1360 J of heat = ?

Solution:

As 36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

36200 J of heat release ≅ 1 gram of reactant

1360 J of heat release ≅ X gram of reactant

Do cross multiplication

X gram of reactant = 1 g x 1360 J / 36200 J

X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

5 0

3 years ago

Can someone please help me on #2

Colt1911 [192]

To much letters and numbers

8 0

3 years ago

What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy

meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created

The equation is:

$\tt \Delta U=Q+W$

Energy owned by the system is expressed as internal energy (U)

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)

The sign rules for heat and work are set as follows:

• The system receives heat, Q +

• The system releases heat, Q -

• The system does work, W -

• the system accepts work, W +

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

$\tt \Delta E=-13+5=-8~kJ$

6 0

3 years ago

algol13

Chechnya. 345. Gcbjshjkfs

3 0

3 years ago

How many grams of butane were in 1. 000 atm of gas at room temperature?

dimaraw [331]

The mass in grams of butane at standard room temperature is 53.21 grams.

<h3>How can we determine the mass of an organic substance at room temperature?</h3>

The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:

PV = nRT

Pressure = 1.00 atm
Volume = 22.4 L
Rate = 0.0821 atm*L/mol*K
Temperature = 25° C = 298 k

1 × 22.4 L = n × (0.0821 atm*L/mol*K× 298 K)

n = 22.4/24.4658 moles

n = 0.91556 moles

Recall that:

number of moles = mass(in grams)/molar mass

mass of butane = 0.91556 moles × 58.12 g/mole

mass of butane = 53.21 grams

Learn more about calculating the mass of an organic substance here:

brainly.com/question/14686462

#SPJ12

3 0

2 years ago