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3 years ago

Look at the circuit diagram. Which of these components is part of the circuit

Physics

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

Explanation:

The switch is the only named part that is in the diagram. Just did this. Hope it helps!

Aneli [31]3 years ago

7 0

You have not provided choices, therefore, I can not provide an exact choice.

However, I will tell you the components of the given circuit and you can choose the one found in the choices you have.

The given circuit is composed of:
1- A battery:
It has the symbol of the long line and short line next to each other. The long line represents the positive pole while the short line represents the negative one. Battery is used to supply power to the circuit
2- An ammeter:
If has the symbol of an "A" in a circle. This device is used to measure the current flowing in the circuit
3- A resistance:
It has the symbol of the zigzag line. Resistance could be any device that consumes the power in the circuit.
4- A switch:
This has the symbol of the line at the bottom of the circuit. In its current status, the switch is off which means that no current is flowing in the circuit. If we connect the open terminal of the switch with the circuit, the switch is said to be on and current would flow in the circuit.

Hope this helps :)

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4 years ago

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2 years ago

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4 years ago

Read 2 more answers

A carbon fiber car bumper is hit by another car with the stress of 106,483 Pa. If carbon fiber has a Young's modulus of 228 x 10

hoa [83]

Answer:

Stress = 4.67 * 10^-7 N/m²

Explanation:

Young's modulus of the material = Stress/Strain

Given

Young's modulus = 228 x 10^9 Pa

Stress = 106,483 Pa

Required

Strain

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Strain = Stress/Young modulus

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3 0

3 years ago

A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. T

Nina [5.8K]

Answer:

a)5.88J

b)-5.88J

c)0.78m

d)0.24m

Explanation:

a) W by the block on spring is given by

W= $\frac{1}{2}$ kx² = $\frac{1}{2}$ (530)(0.149)² = 5.88 J

b) Workdone by the spring = - Workdone by the block = -5.88J

c) Taking x = 0 at the contact point we have U top = U bottom

So, mg $h_o$ = $\frac{1}{2}$ kx² - mgx

And, $h_o$ = ( $\frac{1}{2}$ kx² - mgx )/(mg) = $[\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)$ ]/(0.645x9.8)

$h_o$ = 0.78m

d) Now, if the initial initial height of block is 3 $h_o$

$h_o$ = 3 x 0.78 = 2.34m

then, $\frac{1}{2}$ kx² - mgx - mg $h_o$ =0

$\frac{1}{2}$ (530)x² - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0

265x² - 6.321x - 14.8 = 0

a=265

b=-6.321

c=-14.8

By using quadratic eq. formula, we'll have the roots

x= 0.24 or x=-0.225

Considering only positive root:

x= 0.24m (maximum compression of the spring)

4 0

3 years ago