Ocean waves are hitting a beach at a rate of 3.5 hz. what is the period of the waves?

Which best describes the ages of the rocks on opposite sides of and the same distance from, A Seafloor spreading center?

Genrish500 [490]

Answer;

-The rocks are the same age

Explanation;

Seafloor spreading is the process by which the seafloor moves apart at mid-ocean ridges. Divergent seafloor spreading occurs at this type of plate boundary.

Seafloor spreading and other tectonic activity processes are the result of mantle convection. Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle’s convection currents makes the crust more plastic and less dense.

4 0

2 years ago

Cosmologists study ______.

____ [38]

Your answer is:

<em>The origin, structure, and future of the universe</em>

You can just search up the definition of Cosmology and receive your answer. Hopefully this helps at least a little :3

6 0

3 years ago

Read 2 more answers

An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.

adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

$\Delta x\times \Delta p=\frac{h}{4\pi}$ ...........(1)

where,

$\Delta x$ = uncertainty in position

$\Delta p$ = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

$p=m\times v$

or,

$\Delta p=m\times \Delta v$ .......(2)

Equating 1 and 2, we get:

$\Delta x\times m\times \Delta v=\frac{h}{4\pi}$

$\Delta v=\frac{h}{4\pi \Delta x\times m}$

Given:

m = mass of electron = $9.11\times 10^{-31}kg$

h = Planck's constant = $6.626\times 10^{-34}Js$

radius of atom = $67.0pm=67.0\times 10^{-12}m$ $(1pm=10^{-12}m)$

$\Delta x$ = diameter of atom = $2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m$

Now put all the given values in the above formula, we get:

$\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}$

$\Delta v=4.32\times 10^{5}m/s$

The minimum uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

Now we have to calculate the percentage of the average speed.

Percentage of average speed = $\frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100$

Uncertainty in speed = $4.32\times 10^{5}m/s$

Average speed = $1.3\times 10^{6}m/s$

Percentage of average speed = $\frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100$

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0

3 years ago

Your bike gets a flat tire. Its mass is 10 kg and you are able to accelerate your bike .5 m/s/s. What is the force on the bike..

STALIN [3.7K]

Answer:

50N

Explanation:

Given parameters:

Mass of the bike = 10kg

Acceleration = 5m/s²

Unknown:

Force on the bike = ?

Solution:

To solve this problem, we apply Newton's second law of motion.

Force = mass x acceleration

Force = 10 x 5 = 50N

6 0

2 years ago

In a classical conditioning experiment, you ring a bell but no longer provide dinner to your subject, a beagle. At last, the CS

beks73 [17]

The answer to the given question above is option C. In a classical conditioning experiment, you ring a bell but no longer provide dinner to your subject, a beagle and at last, the CS no longer evokes the CR so therefore, <span> you've accomplished behavioral EXTINCTION. Hope this helps.</span>

4 0

3 years ago

Read 2 more answers