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2 years ago

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Which of the following is a result of a change in pressure? A. Frost wedging B. Chemical feathering C. Oxidation D. Exfoliation

1 answer:

Stells [14]2 years ago

7 0

The answer is D. Exfoliation. Exfoliation is a type of physical or mechanical weathering which is also referred to as release of pressure. It occurs when layers of rock separate from the stripped rocks as an effect of the pressure released during the wearing down of rock particles by friction due to water, wind or ice.

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Dead lifting uses tho muscle fundamentals

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3 years ago

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Tema [17]

Answer:

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2 years ago

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A boat heads due North for 3.00 km to reach a red buoy. It then changes direction and heads in a direction of 30.0 degrees South

Helga [31]

Position of B :

x = 4.66*cos 30 = 4.036

y = 3-4.66*sin 30 = 3-2.33 = 0.67

BC = √y^2+(x-1)^2 = √0.67^2+3.036^2 = 3.109

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6 0

2 years ago

What is the energy released in this B- nuclear reaction 2K-> 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca

Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

$_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{42}\textrm{K}$ = 41.962403 u

Mass of $_{20}^{42}\textrm{Ca}$ = 41.958618 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(41.962403-41.958618)=0.003785u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.003785u)\times c^2$

$E=(0.003785u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=3.526MeV$

Hence, the energy released in the given nuclear reaction is 3.526 MeV.

7 0

3 years ago

The load across a 12 V battery consists of a series combination of three resistors 34 Ω, 42Ω, and 30Ω. What is the total resista

stira [4]

Answer:

The total resistance is 106 Ω and the current in the circuit is 0.11 A.

Explanation:

Given that,

Voltage of the battery, V = 12 V

Resistors 34 Ω, 42Ω, and 30Ω are connected in series.

The total resistance is given by :}

R = 34 + 42 +30

= 106Ω

Let I is the total current in the circuit. Using ohm's law to find it such that,

$I=\dfrac{V}{R}\\\\I=\dfrac{12}{106}\\\\I=0.11\ A$

Hence, the total resistance is 106 Ω and the current in the circuit is 0.11 A.

4 0

2 years ago