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slamgirl [31]
3 years ago
7

20 POINTS 2 QUESTIONS CAN YOU ANSWER THEM ???

Chemistry
2 answers:
Viktor [21]3 years ago
7 0
2. <span>1/8 = (1/2)³ </span>
<span>so it's 3 half lives.</span>
Reika [66]3 years ago
4 0

<u>Answer 1 :</u> The synthesis reaction is, N_2+3H_2\rightarrow 2NH_3

Explanation :

Synthesis reaction : It is a type of reaction in which the reactants present in elemental state react to give a single product.

(1) N_2+3H_2\rightarrow 2NH_3

This is a synthesis reaction.

(2) MgI_2+Br_2\rightarrow MgBr_2+I2

This is a single displacement reaction in which the most reactive element displaces the least reactive element.

(3) KClO_3\rightarrow KCl+O_2

This is a decomposition reaction in which larger reactant decomposes to give two or more products.

(4) HCl+NaOH\rightarrow NaCl+H_2O

This is a neutralization reaction in which an acid and a base react to give a salt and water as a product.

<u>Answer 2 : </u>The number of half-lives it take will be, 3

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = \frac{1}{8}a_o

a_o = Initial amount of the reactant

n = number of half lives

Putting values in above equation, we get:

\frac{1}{8}a_o=\frac{a_o}{2^n}

2^n=8=2^3

n = 3

Therefore, the number of half-lives it take will be, 3

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dimaraw [331]

Answer : The correct statement is:

The density of each piece is the same as that of the original block.

Explanation :

Intensive property : It is defined as a property of substance which does not change as the amount of substance changes.

Examples: Temperature, refractive index, density, hardness, etc.

According to question, if Ana has a block made of pure gold and she cuts this block into two equal pieces then the density of each piece is the same as that of the original block because density is an intensive property that does not changes until and unless material is changed.

That means density remains same as that of the original piece.

Hence, the correct statement is the density of each piece is the same as that of the original block.

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An ion is an atom with a net electrical charge due to ______.
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What are the concentrations of A , A, B , B, and C C at equilibrium if, at the beginning of the reaction, their concentrations a
Elenna [48]

The question is incomplete, here is the complete question:

A reaction

A+B\rightleftharpoons C

has a standard free-energy change of -4.88 kJ/mol at 25°C

What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30 M, 0.40 M and 0 M respectively?

<u>Answer:</u> The equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

<u>Explanation:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_c

where,

\Delta G^o = Standard Gibbs free energy = -4.88 kJ/mol = -4880 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_c = equilibrium constant of the reaction

Putting values in above equation, we get:

-4880J/mol=-(8.3145J/Kmol)\times 298K\times \ln K_c\\\\K_c=7.17

We are given:

Initial concentration of A = 0.30 M

Initial concentration of B = 0.40 M

Initial concentration of C = 0 M

The chemical reaction follows:

                               A+B\rightleftharpoons C

<u>Initial:</u>                 0.30  0.40      0

<u>At eqllm:</u>         0.30-x   0.40-x    x

The expression of equilibrium constant for the above reaction follows:

K_c=\frac{[C]}{[A][B]}

We are given:

K_c=7.17

Putting values in above equation, we get:

7.17=\frac{x}{(0.30-x)\times (0.40-x)}\\\\x=0.183,0.657

Neglecting the value of x = 0.657, because change cannot be greater than the initial concentration

So, equilibrium concentration of A = (0.30-x)=(0.30-0.183)=0.117M

Equilibrium concentration of B = (0.40-x)=(0.40-0.183)=0.217M

Equilibrium concentration of C = x=0.183M

Hence, the equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

5 0
3 years ago
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