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natita [175]
3 years ago
5

Which of the following is an acid? HF KOH LiF NH3

Chemistry
2 answers:
seraphim [82]3 years ago
3 0

The compound HF is an acid. This is because it dissociates in water to give hydrogen ions (H⁺) as the only positively charged ions.

The others dissociate as follows: NH₃  reacts with water to form an alkaline solution NH₄OH.

LiF dissolves to form an ionic solution

KOH dissociates in water to form an alkaline solution.

BARSIC [14]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Acids are the substances or species which upon dissociation given hydrogen ions, that is, H^{+} ions.

For example, HF when dissolved in water then it will dissociate into H^{+} and F^{-} ions.

Whereas both KOH and NH_{3} are base.

And LiF on dissociation will give Li^{+} and F^{-} ions.

Therefore, we can conclude that out of the following HF is an acid.

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Answer:

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7 0
3 years ago
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A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentr
NNADVOKAT [17]

The question is incomplete, the complete question is;

A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentrations, however, several errors were made throughout the procedure. Determine whether these errors would cause the observed boiling point to be increased or decreased relative to the expected boiling point, based on the procedure, or have no effect on the experimental results.

* The flask is washed with water but not thoroughly dried before preparing the solution

* The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

* Some of the prepared solution splashes out of the flask prior to observation of the boiling point

* When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters

Answer:

The flask is washed with water but not thoroughly dried before preparing the solution  - decrease

The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

-increase

Some of the prepared solution splashes out of the flask prior to observation of the boiling point- have no effect

When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters- decrease

Explanation:

If the flask is washed but not dried, then the solution will be further diluted than expected. As a result of this further dilution, the observed boiling point will be less than the expected boiling point because the boiling point depends on the solution's concentration.

If more solute is added than expected, the concentration of the solution is increased and the boiling point also increases above the expected boiling point due to the increase in amount of solute present.

If some of the solution splashes out of the flask prior to boiling, the boiling point is not affected because the concentration of the solution was not altered. The boiling point only changes when the concentration of the solution is changed.

If 55 ml of water is added instead of 50 ml, the solution is now more dilute than expected thereby reducing the concentration of the solution and the boiling point. Remember that, as the concentration of the solution decreases, the boiling point decreases accordingly.

8 0
3 years ago
What is the ph of a saturated zinc hydroxide solution
Tanya [424]
 <span>Ksp = 1.2 x 10^-17 = [Zn2+] [OH-]^2 
Zn(OH)2 <----> Zn2+ + 2OH- 
[Zn2+] = x 
[OH-] = 2x 
1.2 x 10^-17 = (x) ( 2x)^2 = 4 x ^3 
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</span>
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Answer:

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If I helped, a brainliest would be greatly appreciated!

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