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kumpel [21]
2 years ago
9

A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentr

ations, however, several errors were made throughout the procedure. Determine whether these errors would cause the observed boiling point to be increased or decreased relative to the expected boiling point, based on the procedure, or have no effect on the experimental results.
Chemistry
1 answer:
NNADVOKAT [17]2 years ago
8 0

The question is incomplete, the complete question is;

A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentrations, however, several errors were made throughout the procedure. Determine whether these errors would cause the observed boiling point to be increased or decreased relative to the expected boiling point, based on the procedure, or have no effect on the experimental results.

* The flask is washed with water but not thoroughly dried before preparing the solution

* The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

* Some of the prepared solution splashes out of the flask prior to observation of the boiling point

* When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters

Answer:

The flask is washed with water but not thoroughly dried before preparing the solution  - decrease

The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

-increase

Some of the prepared solution splashes out of the flask prior to observation of the boiling point- have no effect

When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters- decrease

Explanation:

If the flask is washed but not dried, then the solution will be further diluted than expected. As a result of this further dilution, the observed boiling point will be less than the expected boiling point because the boiling point depends on the solution's concentration.

If more solute is added than expected, the concentration of the solution is increased and the boiling point also increases above the expected boiling point due to the increase in amount of solute present.

If some of the solution splashes out of the flask prior to boiling, the boiling point is not affected because the concentration of the solution was not altered. The boiling point only changes when the concentration of the solution is changed.

If 55 ml of water is added instead of 50 ml, the solution is now more dilute than expected thereby reducing the concentration of the solution and the boiling point. Remember that, as the concentration of the solution decreases, the boiling point decreases accordingly.

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Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________
bagirrra123 [75]

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as Na^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaCl.

(2) Sodium is carrying +1 charge called as Na^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_3PO_4.

(3) Sodium is carrying +1 charge called as Na^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2SO_4.

(4) Sodium is carrying +1 charge called as Na^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2CO_3.

(5) Potassium is carrying +1 charge called as K^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form KCl.

(6) Potassium is carrying +1 charge called as K^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form K_3PO_4.

(7) Potassium is carrying +1 charge called as K^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form K_2SO_4.

(8) Potassium is carrying +1 charge called as K^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form K_2CO_3.

(9) Calcium is carrying +2 charge called as Ca^{+2} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form CaCl_2.

(10) Calcium is carrying +2 charge called as Ca^{+2} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form Ca_3(PO_4)_2.

(11) Calcium is carrying +2 charge called as Ca^{+2} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form CaSO_4.

(12) Calcium is carrying +2 charge called as Ca^{+2} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form CaCO_3.

(13) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form NH_4Cl.

(14) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form NH_4_3PO_4.

(15) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form NH_4_2SO_4.

(16) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form NH_4_2CO_3.

(17) Iron is carrying +3 charge called as Fe^{+3} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form FeCl_3.

(18) Iron is carrying +3 charge called as Fe^{+3} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form FePO_4.

(19) Iron is carrying +3 charge called as Fe^{+3} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form Fe_2(SO_4)_3.

(20) Iron is carrying +3 charge called as Fe^{+3} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form Fe_2(CO_3)_3.

7 0
3 years ago
C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What
umka21 [38]
The  molar mass  of  the unknown  compound  is   calculated   as   follows

let the unknown  gas be represented by   letter  Y

Rate of C2F4/  rate of  Y  = sqrt of   molar  mass of gas Y/ molar mass of  C2F4

 =  (4.6  x10^-6/ 5.8  x10^-6)  = sqrt  of  Y/ 100

remove  the  square  root  sign  by  squaring  in both  side

(4.6  x  10^-6 / 5.8  x10^-6)^2 =  Y/100

= 0.629 =Y/100

multiply  both side  by  100

Y=  62.9 is  the molar  mass of unknown  gas



5 0
3 years ago
HELPPP MEEEEE!!!POR FAVOR
ikadub [295]

Answer:

A.

Explanation:

hope it helps...

4 0
2 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
What does a dissolved salt look like?
anzhelika [568]

Answer:

Water but with salt

Explanation:

You can’t see it but it’s there

5 0
3 years ago
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