1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
and from this, we find
Solution :
Given :
Mass of the object attached to the spring, m = 2 kg
Velocity of the object as it moves, V = 5 m/s
Amplitude of the object as it swings, A = 2.5 m
We have to find the frequency of the object.
We known,
Therefore,
f = 0.32 Hz
Therefore the frequency of the object is 0.32 hertz when the amplitude of the 2 kg mass is 2.5 m moving a speed of 5 m/s.
Friction and the applied force are not balanced. The 7 N push is countered by the frictional force of 3 N to push the box with a net force of 4 N.