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stiv31 [10]
3 years ago
8

If railroad tracks were built over the boundary of two plates what would happen to the railroad tracks as the plates moved

Physics
1 answer:
Oliga [24]3 years ago
6 0
The railroad tracks will move with the plate boundaries
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The acceleration that the cheeseburger experienced is 20 m/s^2.
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What is the advantage of a free market economy??
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A free market economy<span> has two key </span>advantages<span>. First, it allows for individuals to innovate. Individuals have the freedom to create new ideas, new products, and new services to sell for profit. They are not required to only produce what the government tells them to produce.</span>
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A car drives for 30 km with a speed of 30m/s. How much time does it take the car to travel this distance?
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                   Time  =  (distance)  /  (speed)

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6 0
3 years ago
Can someone give me an example or explanation of calculating energy from voltage? Many thanks!
antoniya [11.8K]
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Additional help:
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[ V = I x R ] V (volts) = I (amps) x R (Ω)

-To find the Current ( I )
[ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

-To find the Resistance ( R )
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I hope that helps to some extent-
7 0
2 years ago
A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0
3 years ago
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