The disadvantages of shared decision making are:
Adopting a wrong advice from a member can lead to a big risk to the company and the business.
Further, increased number of advice also confuses the person, about which to follow and which to ignore.
There is also diffusion of responsibility and lowered efficiency.
Answer:
1) 1.31 m/s2
2) 20.92 N
3) 8.53 m/s2
4) 1.76 m/s2
5) -8.53 m/s2
Explanation:
1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s

2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration

3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.

So the maximum acceleration on the block is

4)As the box slides, it is now subjected to kinetic friction, which is

So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is
28.25 / 16 = 1.76 m/s2
5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2
Answer:
gravitational force
electrostatic force
Explanation:
The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.
The Mutual force of gravitational pull that they exert on each other can be given as:

where:
gravitational constant 
are the masses of individual balloons
the radial distance between the center of masses of the balloons.
But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.
Given as:

where:

are the charges on the individual balloons
R = radial distance between the charges.
Answer:
The answer to your question is below
Explanation:
Data
light speed = 300 000 km/s
a) Express it in scientific notation
to do it, we just move the decimal point 5 places to the left
300 000 = 3.0 x 10 ⁵ km/s
b) Convert this value to meters per hour
(300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1
= 1.08 x 10¹² m/h
c) What distance in centimeters does light travel in 1 s?
data
v = 300 000 km/s
d = ?
t = 1 s
formula v = d/t we clear distance d = vxt
d = 300000 x 1 = 300000 km
d = 300000000 m = 30000000000 cm
First, let's express the movement of Car A and B in terms of their position over time (relative to car B)
For car A: y=20x-200 Car A moves 20 meters every second x, and starts 200 meters behind car B
For Car B: y= 15x Car B moves 15 meters every second and starts at our basis point
Set the two equations equal to one another to find the time x at which they meet:
20x - 200 = 15x
200 = 5x
x= 40
At time x=40 seconds, the cars meet. How far will Car A have traveled at this time?
Car A moves 20 meters every second:
20 x 40 = 800 meters