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professor190 [17]
3 years ago
12

Relationships among organisms have evolved for millions of years. True False

Physics
1 answer:
vladimir2022 [97]3 years ago
3 0
True  in the past years there where cavemen back then we had no pets because we couldn't trust them or we were afraid of them, but no we have pets do to adaptation and us changing.
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Honeybees acquire a positive charge while flying through the air. The rapid motion of the wings through the air provides the "fr
Natali5045456 [20]
Yikes i have no clue
3 0
3 years ago
A projectile is launched from the surface of a planet (mass = 15 x 1024 kg, radius = R = 9.6 x 106 m). What minimum launch speed
Serjik [45]

Answer:

The minimum launch speed is 13366.40 m/s.

Explanation:

Given that,

Mass of planet M=15\times10^{24}\ kg

Radius R= 9.6\times10^{6}\ m

Height = 6R

We need to calculate the speed

Using relation between gravitational force and total energy

-\dfrac{GMm}{6R+R}=\dfrac{1}{2}mv^2-\dfrac{GMm}{R}

\dfrac{}{}mv^2=\dfrac{GMm}{7R}-\dfrac{GMm}{R}

\dfrac{1}{2}mv^2=\dfrac{6GMm}{7R}

v^2=\dfrac{2\times6GM}{7R}

Put the value into the formula

v=\sqrt{\dfrac{2\times6\times6.67\times10^{-11}\times15\times10^{24}}{7\times9.6\times10^{6}}}

v=13366.40\ m/s

Hence, The minimum launch speed is 13366.40 m/s.

6 0
3 years ago
Read 2 more answers
A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete
NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}

From Rayleigh criteria

sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm

The focal length of the camera's lens is 300cm

3 0
3 years ago
12. A frain moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
ziro4ka [17]
  • initial velocity=u=0m/s
  • Final velocity=v=25m/s
  • Time=t=30s

\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \tt\longmapsto Acceleration=\dfrac{25-0}{30}

\\ \tt\longmapsto Acceleration=\dfrac{25}{30}

\\ \tt\longmapsto Acceleration=0.8m/s^2

6 0
3 years ago
Acceleration can be found by computing the slope of a blank vs .time graph
scoundrel [369]
Velocity-time graph
5 0
3 years ago
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